POJ C + + programming problem # 200 output

Programming Question # #: Output 200

Source: Peking University Online Program evaluation system POJ (Coursera statement: The exercises completed on POJ will not count to the final results of Coursera. )

Total time limit: 1000ms memory limit: 1024kB

Describe

Make the following code output a result of 200.

#include <iostream>using namespace Std;class number {public:    int num;    Number (int n=0): num (n) {}//complements your code here};int main () {number    N1 (Ten), N2 ();    Number n3;n3 = n1*n2;    cout << Int (n3) << Endl;    return 0;}

Input

No input required.

Output

The output result is 200.

Sample input

No input required.

Sample output

200

1#include <iostream>2 using namespacestd;3 classNumber {4  Public:5     intnum;6Number (intn=0): num (n) {}7 //Add your code here8     int operator* (Number &N) {9         return  This->num *N.num;Ten     } One     //overloaded type conversion equation, cannot have return value A     operator int() { -         returnnum; -     } the }; -  - intMain () { -Number N1 (Ten), N2 ( -); +Number N3;N3 = n1*N2; -cout <<int(n3) <<Endl; +     return 0; A}

POJ C + + programming problem # 200 output