Calendar
Time Limit: 1000MS |
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Memory Limit: 30000K |
Total Submissions: 12842 |
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Accepted: 4641 |
Description
A calendar is a system for measuring time, from hours and minutes, to months and days, and finally to years and centuries. The terms of hour, day, month, year and century is all units of time measurements of a calender system.
According to the Gregorian calendar, which was the civil calendar in use today, years evenly divisible by 4 are leap years, With the exception of centurial years is not evenly divisible by 400. Therefore, the years 1700, 1800, 1900 and 2100 is not a leap years, but a, a, and 2400 is leap years.
Given the number of days that has elapsed since January 1, a-A.D, your mission is-find the date and the day of the Week.
Input
The input consists of lines each containing a positive integer, which are the number of days that has elapsed since Januar Y 1, A.D. The last line contains a integer−1, which should not being processed.
Assume that the resulting date won ' t is after the year 9999.
Output
For each test case, output one line containing the date and the day of the week in the format of "Yyyy-mm-dd DayOfWeek", W Here "DayOfWeek" must be one of "Sunday", "Monday", "Tuesday", "Wednesday", "Thursday", "Friday" and "Saturday".
Sample Input
1730174017501751-1
Sample Output
2004-09-26 sunday2004-10-06 wednesday2004-10-16 saturday2004-10-17 Sunday
Note: Select day of the Week is Sunday as the base date.
#include <iostream>using namespacestd;intmds[ -]={0, to, -, to, -, to, -, to, to, -, to, -, to};Charweek[8][ -]={"Sunday","Monday","Tuesday","Wednesday","Thursday","Friday","Saturday"};BOOLIsleap (intYear ) { if((year%4==0&&year% -!=0)|| year% -==0) { return true; } return false;}intMain () {intstandard=0; for(intI= -; i<= -; i++) { if(Isleap (i)) standard+=366; Elsestandard+=365; } for(intI=1; i<=6; i++) { standard+=Mds[i]; } if(Isleap ( .)) standard++; Standard+=3;//2016-07-03 is Sunday. intdiff; intDays ; while(cin>>days&&days!=-1) {diff=days-Standard ; Diff++; intYear= -; intD=1; intm=1; while(true) { if(Isleap (year)) {if(days>=366) { days-=366; year++; } Else Break; } Else { if(days>=365) { days-=365; year++; } Else Break; } } while(true) { intms=Mds[m]; if(Isleap (year) &&m==2) {MS++; } if(days>=ms) { days-=MS; M++; } Else Break; } d+=Days ; cout<<year<<"-"; if(m<Ten) cout<<"0"; cout<<m<<"-"; if(d<Ten) cout<<"0"; cout<<d<<" "; if(diff>=0) {diff%=7; cout<<Week[diff]<<Endl; } Else{diff=-diff; Diff%=7; if(diff==0) diff=7; cout<<week[7-diff]<<Endl; } } return 0;}
Poj2080:calendar (calculated date)