poj2505a Multiplication Game

The easy water person goes, the moon is like frost.

Description Stan and Ollie play the game of multiplication by multiplying a integer p by one of the numbers 2 to 9. Stan always starts with P = 1, does he multiplication, then Ollie multiplies the number, then Stan and so on. Before a game starts, they draw an integer 1 < n < 4294967295 and the winner are who first reaches P >= N.

Input each line of input contains one integer number N.

Output for each line of input output one line either
Stan wins.
Or
Ollie wins.
Assuming that both of them play perfectly.

Sample Input

162
17
34012226

Sample Output

Stan wins.
Ollie wins.
Stan wins.

The main idea: Two people take turns playing the game, Stan Initiator, the number p starting from 1, Stan multiplied by a 2-9 number, and then Ollie multiplied by a 2-9 number, until the person who first took p to P>=n when the man won, and when the turn of someone, someone must multiply 2-9 a number.

Problem Solving Ideas:

Game, to find the law, first we easily get in

[2,9] This interval is Stan winning.

[10,18] This interval, is Ollie win

Then the left side of the next interval must be [18+1,. It's Stan's victory.

The interval should be filled in what number, because 18 is a must defeat, so the turn to Stan start, then he can be multiplied by a 9, that is, 18*9, Stan will win.

We can think of 18 as 9*2, which means that the more Stan wants to approach N,ollie, the more he doesn't want him to reach N

So the next interval is [18+1,9*2*9], in fact, to find a law can also find a law

[9*2*9+1,9*2*9*2],ollie win

[9*2*9*2+1,9*2*9*2*9],stan Winning code:

#include <cstdio>
#include <cstring>
#include <iostream>
#include <algorithm>
const int maxn=10000;
using namespace std;
int main (void)
{
    long long num;
    while (~SCANF ("%lld", &num))
    {
        if (num<=9)
        {
            printf ("Stan wins.\n");
            Continue;
        }
        if (num>9&&num<=18)
        {
            printf ("Ollie wins.\n");
            Continue;
        }
        while (num>18)
        {
            num= (num-1)/18+1;
        }
        if (num<=9)
        {
            printf ("Stan wins.\n");
            Continue;
        }
        if (num>9&&num<=18)
        {
            printf ("Ollie wins.\n");
            Continue;
        }
    }
    return 0;
}