Problem 2146 Easy Game (Fzu math AH)

Title Link: http://acm.fzu.edu.cn/problem.php?pid=2146

Problem Description

Fat brother and Maze is playing a kind of special (hentai) game on a string S. Now they would as to count the length of this string. But as both Fat brother and Maze is programmers, they can recognize only the numbers 0 and 1. So instead of judging the length of this string, they decide to judge weather this number is even.

Input

The first line of the date is a integer T, which is the number of the text cases.

Then T cases follow contains a line describe the string S in the treasure map. Not this S only contains lower case letters.

1 <= T <=, the length of the string is less than 10086

Output

For each case, output the case number first, and then output "ODD" if the length of S is ODD, otherwise just output "even" .

Sample Input4wellthisisthesimplestprobleminthiscontest Sample Outputcase 1:evencase 2:oddcase 3:oddcase 4:odd

The code is as follows:

#include <cstdio> #include <cstring>int main () {    char s[10087];    int cas = 0;    int t;    scanf ("%d", &t);    while (t--)    {        scanf ("%s", s);        int Len=strlen (s);        printf ("Case%d:", ++cas);        if (len%2)            printf ("odd\n");        else            printf ("even\n");    }    return 0;}

Problem 2146 Easy Game (Fzu math AH)