Python <---> small topic exercises, python ---
Job 1:
With the * dictionary * output directory, you can select a directory to enter. You can roll back and exit!
# Conding: utf8
Menu = {'beijing': {'changping ': {'shahe': {'changping maternal and children ', }}, 'haidian': {'haidian 1 ': {'haidian 2's },},}# dictionary nesting
Current_layer = menu # use this variable to record the location of the current Layer
Pre_menu = [] # use [] to record each layer
While True:
For k in current_layer:
Print (k)
Choice = input ('>>>>>>>:'). strip () # Remove the spaces of the input options.
If len (choice) = 0: # Use The len Length to determine whether the user has entered
Continue
If choice in current_layer:
Pre_menu.append (current_layer)
Current_layer = current_layer [choice]
Elif choice = 'B ':
If len (pre_menu)> 0: # if len (pre_menu) is greater than 0, a directory can be returned.
Current_layer = pre_menu.pop () # Use pop to pop up the above layer.
Elif choice = 'q ':
Exit () |
Assignment 2
Small list exercise: implements the shopping cart Function
Product_list = [['iphone ', 6500], ['mobli', 5000], ['huawei', 4000], ['oppo ', 300], ['vivo ', [100]
Money = int (input ('Please input your money :'))
Got_list = []
While True:
For I, v in enumerate (product_list): # display a two-dimensional series, 0... 1... 2 ....
Print (I, v)
Choice_goods = input ('which good do you want to get :')
If choice_goods.isdigit (): # determine whether the number is input.
Choice_goods = int (choice_goods)
If choice_goods <len (product_list) and choice_goods> = 0: # condition judgment to check whether the condition is out of the range
If money> product_list [choice_goods] [1]: # if the money is higher than the price of the item
Money-= product_list [choice_goods] [1] # Calculate the balance
Got_list.append (product_list [choice_goods] [0]) # Add the purchased item to the list
Print ('You good is % s' % (got_list ))
Print ('You left money is: % s' % (money ))
Print ('')
Print ('')
Else:
Print ('You do not have enough money to bu anything! ')
Print ('\ n ')
Else:
Print ('we do not have this good ')
Print ('\ n ') |
Assignment 3
Bubble algorithm small exercise
A_list = [9, 8, 7, 6, 5, 4, 3, 2, 1]
For j in range (len (a_list)-1): # in the second step, you need len (a_list)-1 to arrange a number in each loop.
# Step 1: The primary algorithm does not subtract j, and each cycle is compared from start to end. If j is subtracted, no comparison is required for the following sorting.
For I in range (len (a_list)-1-j ):
If a_list [I]> a_list [I + 1]: # maximum number of rows to the end
A_list [I], a_list [I + 1] = a_list [I + 1], a_list [I] # use a, B = B, a to call
Print (a_list) |
