Python calculates the square root of arithmetic and the approximate number, and python returns the square root of arithmetic.

Python calculates the square root of arithmetic and the approximate number, and python returns the square root of arithmetic.

I. square root of arithmetic

a=x=int(raw_input('Enter a number:'))if x >= :while a*a < x:a = a + if a*a != x:print x,'is not a perfect square'else:print aelse:print x,'is a negative number'

Ii. Estimate the approximate number

Method 1:

divisor = [ ]x=int(raw_input('Enter a number:'))i= while i<=x: if x%i ==:divisor.append(i)i = i +print 'divisor:',divisor

Method 2:

Divisor = [] x = int (raw_input ('enter a number: ') for I in range (, x +): if x % I =: divisor. append (I) # This line can also be changed to divisor = divisor + [I] print 'divisor: ', divisor

The following describes the Python sqrt () function.

Description

The sqrt () method returns the square root of the number x.

Syntax

The syntax of the sqrt () method is as follows:

import mathmath.sqrt( x )

Note: sqrt () cannot be accessed directly. You need to import the math module and call this method through static objects.

Parameters

X -- numeric expression.

Return Value

Returns the square root of x.

Instance

The following shows an instance using the sqrt () method:

#!/usr/bin/pythonimport math # This will import math moduleprint "math.sqrt(100) : ", math.sqrt(100)print "math.sqrt(7) : ", math.sqrt(7)print "math.sqrt(math.pi) : ", math.sqrt(math.pi)

The output result is as follows:

math.sqrt(100) : 10.0math.sqrt(7) : 2.64575131106math.sqrt(math.pi) : 1.77245385091

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