Python core programming, Version 2, 160th page, Chapter 6 exercises

I will share with you the answers to my core Python programming exercise.
Because it is not from official resources, it is your own exercises. It may be wrong or not the best solution.

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6-1.
String. Is there a string method or function in the string module that can help me identify whether the next string is part of another large string?
[Answer]
The member operator is used to determine whether a character or a string (the character in) appears in another string. If yes, True is returned. If no, False is returned. Note that the member operator is not used to determine whether a string contains another string. Such a function is completed by the find (), index (), rfind (), and rindex () functions.
>>> 'Bc' in 'abc'
True
>>> 'N' in 'abc'
False

 

6-2.
String identifier. Modify the idcheck. py script in the example of 6-1 to detect an identifier and identify the Python keyword. For the next requirement, you can use the keyword module (especially keyword. kwlist.
[Evaluation]
I suspect that the original intention of the question is to modify the script so that it can detect an identifier with a length greater than or equal to one.
[Reference]
Idcheck. py script
Import string

Alphas = string. letters + '_'
Nums = string. digits

Print 'Welcome to the Identifier Checker v1.0'
Print 'testees must be at least 2 chars long .'

MyInput = raw_input ('identifier to test? ')

If len (myInput)> 1:

If myInput [0] not in alphas:
Print ''' invalid: first symbol must be alphabetic '''

Else:
For otherChar in myInput [1:]:

If otherChar not in alphas + nums:
Print ''' invalid: first symbol must be alphabetic '''
Break
Else:
Print 'Okay as an identifier'

[Reference] About keyword. kwlist

>>> Import keyword

>>> Dir (keyword)
['_ All _', '_ builtins _', '_ doc _', '_ file __', '_ name _', 'iskeyword', 'kwlist', 'main']

>>> Keyword. kwlist
['And', 'assert ', 'Break', 'class', 'contine', 'def', 'del', 'elif', 'else ', 'Wait t', 'exec ', 'Finally', 'for ', 'from', 'global', 'if', 'import', 'in', 'is ', 'lambda ', 'not', 'or', 'pass', 'print ', 'raise', 'Return ', 'try', 'while', 'yield ']
>>>
[Answer]
The Code is as follows:
Import string
Import keyword

Alphas = string. letters + '_'
Nums = string. digits

Print 'Welcome to the Identifier Checker v2.0'
Print 'testees must be at least 1 chars long .'

MyInput = raw_input ('identifier to test? ')

IsKeyword = False
IsIdentifier = False

If len (myInput)> = 1:

If myInput [0] not in alphas:
Print ''' invalid: first symbol must be alphabetic '''
IsIdentifier = False
Else:
For otherChar in myInput [1:]:

If otherChar not in alphas + nums:
Print ''' invalid: remaining symbols must be alphabetic '''
IsIdentifier = False
Break
Else:
IsIdentifier = True

If myInput in keyword. kwlist:
Print '"% s" is a keyword of python' % myInput
IsKeyword = True
If isIdentifier and (not isKeyword): print 'Okay as an identifier'

 

6-3.
Sort.
(A) enter a string of numbers in ascending order.
(B) SAME AS. However, it should be arranged in lexicographically ascending order.
[Answer]
(A) The Code is as follows:
AList = raw_input ('Please input numbers, separated by space ...')
BList = []
For I in aList. split (''):
BList. append (int (I ))
BList. sort ()
Print bList [:-1]
(B) The Code is as follows:
AList = raw_input ('Please input numbers, separated by space ...')
BList = []
For I in aList. split (''):
BList. append (I)
BList. sort ()
Print bList [:-1]
[Evaluation]
I checked the meaning of the Lexicographic Order, which seems to be inconsistent with the meaning of the question.

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