Python daily Practice (2): Find all links in HTML (Xpath, regular two versions)

To find out the specific content in the Hrml file, you first need to observe what the content is and where it is, so you can find it.

Assume that the HTML file name is: "1.html", the href attribute is all in the a tag.

Regular version:

# Coding:utf-8 Import Rewith Open ('1.html','r') as F:     == Re.findall (R'href= "(. *?)" ' , data)  for inch Result:     Print each

XPath version:

#Coding:utf-8 fromlxmlImportEtreewith Open ('1.html','R') as F:data=f.read () selector=etree. HTML (data) result= Selector.xpath ('//a/@href') foreachinchResult:Printeach

The XPath version is more than the regular version of the page, this HTML file seems to be a bit long posted up when the show 502, solve.

Does it seem that the editor doesn't have a place to upload attachments?

Python daily Practice (2): Find all links in HTML (Xpath, regular two versions)