Python-Detects the inclusion of strings

Detects the inclusion between strings.

 

 

 

PythonCan detect the inclusion problem between strings.

ContainsAny, As long as it contains any character;

ContainsOnly, All characters are included;

ContainsAll, Including all;

 

Code:

 

#-*-Coding: UTF-8-*-''' Created on 2014.5.25 @ author: C. l. wang ''' has any ''' def ininsany (seq, aset): for c in seq: if c in aset: return True return Falseimport itertoolsdef containsAny2 (seq, aset): for item in itertools. ifilter (aset. _ contains __, seq): return True return Falsedef containsAny3 (seq, aset): return bool (set (aset ). intersection (seq) ''' all exist ''' def containsOnly (seq, aset): for c in seq: If c not in aset: return False return True ''' contains all ''' def containsAll (seq, aset): # print (set (aset ). difference (seq) return not set (aset ). difference (seq) import stringnotrans = string. maketrans ('','') def containsAny4 (astr, strset): return len (strset )! = Len (strset. translate (notrans, astr) def containsAll2 (astr, strset): return not strset. translate (notrans, astr) if _ name _ = '_ main _': L1 = [1, 2, 3, 4] L2 = [5, 6, 7, 8] L3 = [1, 4, 7, 10] print (L1 constains any in L2: + str (containsAny (L1, L2 ))) print (L1 constains any in L3: + str (containsAny (L1, L3) print (L1 constains any in L2 (2): + str (containsAny2 (L1, l2) print (L1 constains any in L3 (2): + str (containsAny2 (L1, L3) print (L1 constains any in L2 (3 ): + str (containsAny3 (L1, L2) print (L1 constains any in L3 (3): + str (containsAny3 (L1, L3) L4 = [1, 1, 2, 2, 3, 4] L5 = [1, 1, 2, 2, 3, 4, 5] print (L1 constains only in L4: + str (containsOnly (L1, l4) print (L1 constains only in L5: + str (containsOnly (L1, L5) print (L1 constains all in L4 (2 ): + str (containsAll (L1, L4) print (L1 constains all in L5 (2): + str (containsAll (L1, L5) pass

Output:

 

 

L1 constains any in L2 : FalseL1 constains any in L3 : TrueL1 constains any in L2 (2) : FalseL1 constains any in L3 (2) : TrueL1 constains any in L2 (3) : FalseL1 constains any in L3 (3) : TrueL1 constains only in L4 : TrueL1 constains only in L5 : TrueL1 constains all in L4 (2) : TrueL1 constains all in L5 (2) : False