Python determines if the Linux host on Xen virtualization is a virtual machine

Cloud computing uses Xen virtualization, and sometimes we have to roughly determine if the host is a virtual machine.

Windows host, direct Explorer to view hardware devices.

And Linux hosts can be monitored with Python scripts

Judging Openvz/xen pv/uml

Judge Openvz/xen Pv/uml is the easiest, directly check the/PROC under the relevant directories and files can be known, such as OpenVZ VPS will have/proc/vz this file, Xen PV virtual machine will have/proc/xen/this directory, and the directory has Some things; printing/proc/cpuinfo on UML will find UML flags. Wrote a simple Python script to detect:

#!/usr/bin/python# check if a linux system running on a virtual  machine  (OPENVZ/XEN PV/UML) Import sys, osdef main ():     if  os.getuid ()  != 0:        print  "Must be  run as root "        sys.exit (0)      # check openvz/virtuozzo    if os.path.exists ("/proc/vz"):         if not os.path.exists ("/PROC/BC"):             print  "Openvz container"          else:            print   "Openvz node"     # check Xen    if  Os.path.exists ("/proc/xen/capabilities"):         if  (Os.path.getsize ("/proc/xen/capabilities")  >  0):            print  "xen dom0"          else:             print  "Xen domu"     # check user mode linux   (UML)     f = open ("/proc/cpuinfo",  "R");  t = f.read ();  f.close ()     if  (T.find ("UML")  > 0):         print  "UML" if __name__== "__main__":     main ()

Python determines if the Linux host on Xen virtualization is a virtual machine