Python finds a number that is equal to the inverse of the sequence (for example, 28682)

Directly on the code

#coding: Utf-8

def f1 (x):#定义一个函数, find numbers that are equal to the reverse order

If Type (x)!=int:#如果函数参数不是整型, exiting the program

Exit (' must a int type ')

X=STR (x)

Lix=list (x)

Str1= "

I=len (LIX)-1

While I <len (LIX) and I >=0:#循环的作用是将字符串从尾到头重新组合相加一次

Str1=str1+lix[i]

I=i-1

If x==str1:#如果源字符串和转换后的字符串一样, can be determined to find the positive and negative are equal to the number

return x

List1=range (900,1000)

Print filter (f1,list1)#使用filter函数 to filter out the negative numbers.

Execution Result:

[909, 919, 929, 939, 949, 959, 969, 979, 989, 999]

Python finds a number that is equal to the inverse of the sequence (for example, 28682)