Python title: Fibonacci number calculation; title: queued sequential output; title: Creation of the legal parentheses combination; Title: User Login (three chance)

Fibonacci Series Calculation B description

The Fibonacci sequence is as follows:

F (0) = 0, f (1) = 1

F (n) = f (n-1) + f (n-2)

Write a function that computes the Fibonacci sequence, using a recursive method to output all Fibonacci sequence elements that do not exceed n

Call the function above to complete the following functions:

The user enters an integer n, outputs all Fibonacci sequence elements not exceeding n, the elements and averages of the output sequence, and outputs in order, separated by commas and spaces

This topic is automatic review, please strictly follow the requirements of the specification of input and output.

def Jebona (n):ifn==0:          return 0elif N==1:          return 1     Else:          returnJebona (n1) + Jebona (n2) n=eval (input ()) Len=0ret=0ls=[] forIinchRange0, n+1): Ret= ret +Jebona (i) Len+=1ls.append (str (Jebona (i))) Ls.append (str (ret)) Ls.append (str (ret//len))Print", ". Join (LS)

Queued Sequential Output description

A group of people queued, each of them is described by a pair of integers (h, k), where h represents the height of the person, and K indicates the total number of people in the queue that is not less than the person in front of the person.

Implement an algorithm to output this queue in the correct order.

Input:

[[7,0], [4,4], [7,1], [5,0], [6,1], [5,2]]

Output:

[[5,0], [7,0], [5,2], [6,1], [4,4], [7,1]]

 from operator  == Itemgetter (1= Itemgetter (0), reverse == []for   in queue:    output.insert (item[1], item) print (output)

The generation description of the legal parentheses combination

Given the number of parentheses N, the writer generates all well-formed combinations of parentheses.

def foo (output, open, close, pairs):ifOpen = = Pairs and close = =pairs:ls.append (Output)Else:          ifopen<Pairs:foo (Output+"(", open+1, close, pairs)ifclose<Open:foo (Output+")", Open, close+1, pairs) n=eval (input ()) LS=[]foo ("',0,0, N) print (LS)

User Login (three chance) description

Give the user three times the opportunity to enter the user name and password, the following requirements:

1) Enter the first line to enter the user name ' Kate ', the second line to enter a password of ' 666666 ', the output ' login success! ', exit the program;

2) When a total of 3 input user name or password incorrect output "3 times user name or password is wrong!" Exits the program. ”。

#name_passwd. Pyi=0ret=1 forIinchRange0,3): Name=input () passwd=input ()ifName = ="Kate"and passwd = ="666666": Ret=0;  Break;ifRET = =0: Print ("Login Successful! ")Else: Print ("3 times the username or password is wrong! Exits the program. ")

Python title: Fibonacci number calculation; title: queued sequential output; title: Creation of the legal parentheses combination; Title: User Login (three chance)