Python Hamlet word Count Cloud

Def getText ():  #赋予txt哈姆雷特小说-All English lowercase-full symbol variable space-Returns TXT        txt = open (' Hamlet.txt ', ' R '). Read () #注意文本的路径        txt = Txt.lower () #文本字符全部转变为小写字母 for        ch in '! ' #$%& () *+,-./:;<=>[email protected][\\]^_ ' {|} ~ ':            txt = txt.replace (ch, "") #使用空格字符替换掉文本中所有特殊字符        return txthamlettxt = GetText () #调用函数words = Hamlettxt.split () #以空字符做列表返回counts = {} #创建一个空字典for word in words:    Counts[word] = Counts.get (word,0) + 1#get do not create word as the underlying value 0 + in Word 1, if get is on the value of Word add 1, and then update the dictionary items = list (Counts.items ()) #字典的键值对变成列表items. Sort (Key=lambda x:x[1],reverse=true) # Arranged in the number of occurrences, from large to small for I in range:    word,count = items[i]    print (' {0:<10},{1:>5} '. Format (Word,count))

　　

Python Hamlet word Count Cloud