Python Method for regularly executing a specified function

Source: Internet
Author: User
This article describes how to regularly execute a specified function in python, and describes how to use the sleep method for delayed execution in Python, for more information about how to regularly execute a specified function in python, see the example in this article. Share it with you for your reference. The specific implementation method is as follows:

# time a function using time.time() and the a @ function decorator# tested with Python24  vegaseat  21aug2005import timedef print_timing(func):  def wrapper(*arg):    t1 = time.time()    res = func(*arg)    t2 = time.time()    print '%s took %0.3f ms' % (func.func_name, (t2-t1)*1000.0)    return res  return wrapper# declare the @ decorator just before the function, invokes print_timing()@print_timingdef getPrimeList(n):  """ returns a list of prime numbers from 2 to < n using a sieve algorithm"""  if n < 2: return []  if n == 2: return [2]  # do only odd numbers starting at 3  s = range(3, n+1, 2)  # n**0.5 may be slightly faster than math.sqrt(n)  mroot = n ** 0.5  half = len(s)  i = 0  m = 3  while m <= mroot:    if s[i]:      j = (m*m-3)//2      s[j] = 0      while j < half:        s[j] = 0        j += m    i = i+1    m = 2*i+3  return [2]+[x for x in s if x]if __name__ == "__main__":  print "prime numbers from 2 to <10,000,000 using a sieve algorithm"  primeList = getPrimeList(10000000)  time.sleep(2.5)"""my output -->prime numbers from 2 to <10,000,000 using a sieve algorithmgetPrimeList took 4750.000 ms"""

I hope this article will help you with Python programming.

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