Python notes 6-%u60a0 and \u60a0 similar to Unicode decoding

Objective

Sometimes the return value from the interface is encoded in a format similar to "%u4e0a%u6d77%u60a0%u60a0", not the Unicode encoding in Python.

The Unicode encoding inside Python should be this format: \u4e0a\u6d77\u60a0\u60a0

Unicode encoding-python2

1. First look at the Unicode encoding for Python: \u60a0, this is the beginning of the \u, the English is lowercase

# coding:utf-8# 前面加u可以直接打印中文a = u"\u4e0a\u6d77\u60a0\u60a0"print(a)# 字符串需decode成默认unicode编码b = r"\u4e0a\u6d77\u60a0\u60a0"print(b.decode("unicode_escape"))

2. If you add a U in front of the string, meaning to convert to Unicode encoding, if you get a string prototype, then you need to decode decoding to Unicode encoding, Python, the default Unicode encoding name is Unicode_escape

Replace%-python2

1. If this is the code with the percent, first replace, this is the Unicode encoding, although the English characters inside is the size, fortunately here is not case-sensitive.

# coding:utf-8c = "%u4E0A%u6D77%u60A0%u60A0"# 解决办法一：替换%d = c.replace("%", "\\")print(d.decode('unicode_escape'))

Solution Two: UNICHR

1. First cut into a single character, and then converted to Chinese with UNICHR, and then into a string, this is a bit complicated

# coding:utf-8def switch_to_ch(f):    '''转换成中文'''    g = f.split("%u")[1:]    h = [''+unichr(int(i, 16)) for i in g]    return "".join(h)if __name__ == "__main__":    f = "%u4e0a%u6d77%u60a0%u60a0"    ch = switch_to_ch(f)    print(ch)

Python3 decoding

1.python3 default encoding is Unicode, this is not the same as python2, if directly to the string decode will error: attributeerror: ' str ' object has no attribute ' Ecode '

2.python3 first encode into Utf-8 code, and then decode into the default Unicode can be

3. Code reference

# coding:utf-8c = "%u4E0A%u6D77%u60A0%u60A0"# python3解决办法：替换%d = c.replace("%", "\\")print(d.encode("utf-8").decode("unicode_escape"))

Python notes 6-%u60a0 and \u60a0 similar to Unicode decoding