[Python] Several ways to resolve a domain name from a URL

Several ways python resolves a domain name from a URL

Find the domain name from the URL, the first thought is to use the regular, and then look for the corresponding class library. With regular parsing there are many incomplete places, the URL has a domain name, the domain name suffix has been increasing and so on. Through Google to find several methods, one is to use the Python module and the regular combination to resolve the domain name, the other is to enable the third party to write the parsing module directly parse out the domain name.

The URL to resolve

urls = [" http://meiwen.me/src/index.html "," http://1000chi.com/game/index.html ", "Http://see.xidian.edu.cn/cpp/html/1429.html", "https://docs.python.org/2/howto/regex.html", "" "https:/ /www.google.com.hk/search?client=aff-cs-360chromium&hs=tsj&q=url%e8%a7%a3%e6%9e%90%e5%9f%9f%e5%90%8dre &OQ=URL%E8%A7%A3%E6%9E%90%E5%9F%9F%E5%90%8DRE&GS_L=SERP.3 ... 74418.86867.0.87673.28.25.2.0.0.0.541.2454.2-6j0j1j1.8.0 .... 0...1c.1j4.53.serp. 26.2.547.IUHTJ4UOYHG "" "," file:///D:/code/echarts-2.0.3/doc/example/tooltip.html "," HTTP://API.MONGODB.O Rg/python/current/faq.html#is-pymongo-thread-safe "," https://pypi.python.org/pypi/publicsuffix/"," http: 127.0.0.1:8000 "] 

How to use urlparse+ regular

Import refrom urlparse Import Urlparsetophostpostfix = ('. com ', '. La ', '. Io ', '. Co ', '. Info ', '. Net ', '. org ', '. Me ', '. mobi '    , '. us ', '. Biz ', '. xxx ', '. Ca ', '. co.jp ', '. com.cn ', '. net.cn ', '. org.cn ', '. mx ', '. tv ', '. ws ', '. Ag ', '. Com.ag ', '. Net.ag ', '. Org.ag ', '. am ', '. Asia ', '. at ', '. is ', '. com.br ', '. net.br ', '. Bz ', '. com.bz ', '. net.bz ', '. CC ', '. com.co ', '. net.co ', '.    Nom.co ', '. de ', '. Es ', '. com.es ', '. nom.es ', '. org.es ', '. eu ', '. FM ', '. Fr ', '. GS ', '. In ', '. co.in ', '. firm.in ', '. Gen.in ', '. Ind.in ', '. net.in ', '. org.in ', '. it ', '. Jobs ', '. JP ', '. Ms ', '. com.mx ', '. nl ', '. Nu ', '. co.nz ', '. net.nz ', '. org.nz ', '. Se ', '. TC ', '. tk ', '. tw ', '. com.tw ', '. idv.tw ', '. org.tw ', '. HK ', '. co.uk ', '. ' me.uk ', '. org.uk ', '. VG ', '. com.hk ', regx = R ' [ ^\.] + (' + ' | '). Join ([H.replace ('. ', R ' \. ') for h in Tophostpostfix]) + ') $ ' pattern = Re.compile (regx,re. IGNORECASE) print "--" *40for url in urls:parts = Urlparse (URL) host = Parts.netloc m = Pattern.search (host) re s = M.group () if M else Host print "UNKONW" if not res else res

The results of the operation are as follows:

meiwen.me1000chi.comsee.xidian.edu.cnpython.orggoogle.com.hkunkonwmongodb.orgpython.org127.0.0.1:8000

It's basic to accept

Urllib to parse the domain name

import urllibprint "--"*40for url in urls:    proto, rest = urllib.splittype(url)    res, rest = urllib.splithost(rest)    print "unkonw" if not res else res

The results of the operation are as follows:

meiwen.me1000chi.comsee.xidian.edu.cndocs.python.orgwww.google.com.hkunkonwapi.mongodb.orgpypi.python.org127.0.0.1:8000

will bring the www. Also need further analysis to

Using a third-party module TLD

from tld import get_tldprint "--"*40for url in urls:    try:        print  get_tld(url)    except Exception as e:        print "unkonw"

Operation Result:

meiwen.me1000chi.comxidian.edu.cnpython.orggoogle.com.hkunkonwmongodb.orgpython.orgunkonw

The results are acceptable.

Other parsing modules that you can use:

• Tld
• Tldextract
• Publicsuffix

This article is derived from "Orangleliu notebook " Blog, be sure to keep this source http://blog.csdn.net/orangleliu/article/details/39545821

[Python] Several ways to resolve a domain name from a URL