Python Study Notes 15: Date and Time Processing notes, python Study Notes

Python Study Notes 15: Date and Time Processing notes, python Study Notes

#-*-Coding: UTF-8-*-import datetime # date def dateadd_day (days) for the given date to the next N days: d1 = datetime. datetime. now () d3 = d1 + datetime. timedelta (days) return d3 # Yesterday def getYesterday (): today = datetime. date. today () oneday = datetime. timedelta (days = 1) yesterday = today-oneday return yesterday # today def getToday (): return datetime. date. today () # Get the date of the previous day of the given parameter, and return a listdef getDaysBefore (num): today = datetime. date. today () Oneday = datetime. timedelta (days = 1) li = [] for I in range (0, num): # Today minus one day, one day minus today = today-oneday # convert the date to the string li. append (datetostr (today) return li # convert string to datetime Type def strtodatetime (datestr, format): return datetime. datetime. strptime (datestr, format) # convert time to a string in the format of 2015-02-02def datetostr (date): return str (date) [0: 10] # convert time to a string, format: 2015-02-02def datetostr_secod (date): return str (date) [0: 19] # Two date phases How many days are there, for example, 2015-2-04 and 2015-3-1def datediff (beginDate, endDate): format = "% Y-% m-% d" bd = strtodatetime (beginDate, format) ed = strtodatetime (endDate, format) oneday = datetime. timedelta (days = 1) count = 0 while bd! = Ed: ed = ed-oneday count + = 1 return count # Second def datediff_seconds (beginDate, endDate) for the difference between two dates ): format = "% Y-% m-% d % H: % M: % S" if "" not in beginDate or ':' not in beginDate: bformat = "% Y-% m-% d" else: bformat = format if "" not in endDate or ':' not in endDate: eformat = "% Y-% m-% d" else: eformat = format starttime = strtodatetime (beginDate, bformat) endtime = strtodatetime (endDate, eformat) ret = endtime-starttime return ret. days * 86400 + ret. seconds # Get all time in two time periods and return listdef getDays (beginDate, endDate): format = "% Y-% m-% d" begin = strtodatetime (beginDate, format) oneday = datetime. timedelta (days = 1) num = datediff (beginDate, endDate) + 1 li = [] for I in range (0, num): li. append (datetostr (begin) begin = begin + oneday return li # obtain the current year as a string def getYear (date = datetime. date. today (): return str (date) [0: 4] # obtain the current month as a string def getMonth (date = datetime. date. today (): return str (date) [] # obtain the current day as a string def getDay (date = datetime. date. today (): return str (date) [8: 10] # obtain the current hour as a string def getHour (date = datetime. datetime. now (): return str (date) [11: 13] # obtain the current minute as a string def getMinute (date = datetime. datetime. now (): return str (date) [] # obtain the current second as a string def getSecond (date = datetime. datetime. now (): return str (date) [17:19] def getNow (): return datetime. datetime. now () print dateadd_day (10) #16:41:13. 275000 print getYesterday () # 2015-02-03print getToday () # 2015-02-04print getDaysBefore (3) #['2017-02-03 ', '2017-02-02 ', '2017-02-01 '] print datediff ('2017-2-01', '2017-10-05 ') #2015 print datediff_seconds ('2017-02-04', '2017-02-05 ') #86400 print datediff_seconds ('2017-02-04 22:00:00 ', '2017-02-05') #2015 print getDays ('2017-2-03 ', '2017-2-05 ') #['2017-02-03 ', '2017-02-04', '2017-02-05 '] print datetostr_secod (getNow () #2015-02-04 16: 46: 47 print str (getYear (dateadd_day (-50) + '-' \ + getMonth () + '-' \ + getDay () + ''\ + getHour () + ':' \ + getMinute () + ':' \ + getSecond () #16: 59: 04 print getNow () #16:46:47. 454000

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