Python write Level 3 menu

Python write Level 3 menu

#-*-Coding: UTF-8-*-_ author _ = 'am _ mm_NO.1 'import rememu = {"Northeast": {"Jilin Province": {"Jilin City ": ['Jilin city 1', 'Jilin city 2'], "Changchun": ['changchun 1 ', 'changchun 2'],}, "Liaoning Province": {"Shenyang ": ['shenyang 1', 'shenyang 2', 'shenyang 3'], "Dalian": ['dalian 1', 'dalian 2'],},}, 'North China': {'hebei province ': {'langfang': ['langfang 1', 'langfang 2'], 'baoding ': ['baoding 1 ', 'baoding 2'] ,}, 'inner Mongolia ': {'hohhot': ['hohhot 1', 'hohhot 2', 'hohhot 3'], 'baotou ': ['baotou 1', 'baotou 2'] },},} flag = Truewhile flag: # global variable, set to jump out of the entire loop for I, v in enumerate (memu. keys (): # traverse the first dictionary print I, v # print the first key, value num_1 = raw_input ("Enter the first menu number and press q to exit :"). strip () # accept keyboard input if num_1 = 'q': flag = False break if num_1.isdigit (): num_1 = int (num_1) if num_1 <= len (memu ): key_1 = memu. keys () [num_1] while flag: for i1, v1 in enumerate (memu [key_1]): print i1, v1 num_2 = raw_input ("Enter the Level 2 menu number, press q to exit. B returns :"). strip () if num_2 = 'q': flag = False break if num_2 = 'B': break if num_2.isdigit (): num_2 = int (num_2) if num_2 <= len (memu [key_1]): key_2 = memu [key_1]. keys () [num_2] while flag: for i2, v2 in enumerate (memu [key_1] [key_2]): print i2, v2 num_3 = raw_input ("Enter the Level 3 menu number, press q to exit. B returns :"). strip () if num_3 = 'q': flag = False break if num_3 = 'B': break if num_3.isdigit (): num_3 = int (num_3) if num_3 <= len (memu [key_1] [key_2]): key_3 = memu [key_1] [key_2]. keys () [num_3] while flag: for i3, v3 in enumerate (memu [key_1] [key_2] [key_3]): print i3, v3 num_4 = raw_input ("Exit by q, B returns :"). strip () if num_4 = 'q': flag = False break if num_4 = 'B': break