Python3 regular match [^ABC] and (?! ABC) differences (exclude multiple characters as a whole match)

Purpose: To find a string that is not ABC after the number

If 1AB meets the requirements, 2ABC does not meet the requirements

1str ='1ab'2out = Re.match (r'\d+ (?! ABC)', str)3 4STR1 ='1ABC'5OUT1 = Re.match (r'\d+ (?! ABC)', str1)6 7 Print('Out :', out)8 Print('OUT1:', OUT1)9 #Ten #Out : <_sre. Sre_match object; span= (0, 1), match= ' 1 ' > One #Out1:none A #

If you put (?! ABC) instead of [^ABC], the effect is as follows:

1str ='1ab'2OUT3 = Re.match (r'\D+[^ABC]', str)3 4STR1 ='1ABC'5Out4 = Re.match (r'\D+[^ABC]', str1)6 7 Print('Out :', OUT3)8 Print('OUT1:', Out4)9 Ten # One #Out3:none A #Out4:none

Python3 regular match [^ABC] and (?! ABC) differences (exclude multiple characters as a whole match)