Question Fourth: Enter a certain date of the year, Judge this day is the first days of the year?

#输入某年某月某日, judge that day is the first of the year.
"' Thinking: First, the date is divided into the input or a piece of input, think of if a piece of input may also need to split to find the date
So it is better to divide the input; then consider the number of days that are in fact the number of days of the month and the number of days of the month (such as: July 5 is the first 6-month days plus 5)
So the next question is how to find the sum of the days of the first few months, where we use a list to store the number of days in the first few months,
LIST=[0,31,59,90,120,151,181,212,243,273,304,334,365], then July 5 is the first few days can be simply expressed: 5+list[month-1].
Also need to consider is leap year or excepting, leap year February is 29 days, leap year judgment condition: (year%4==0 and year%100!=0) | | Year%400==0 ' "

#必须首先转化成整型 because input () defaults to character type
#and和or的使用
#输入时合法的判断

#方法一: First verify that the date entered is correct, the direct output of a list of conditions, is a leap year and then add a
'''
Year=int (Input (' Input year: ') #首先判断: Whether the date entered is legal
if (year>0):
Month=int (Input (' Input month: '))
if (0<month<13):
Day=int (Input (' Input day: '))
DAYLIST=[31,29,31,30,31,30,31,31,30,31,30,31] #daylist为限制天数做准备, the number of days per month is a range
if (0<day<=daylist[month-1]):
Days=0
LIST=[0,31,59,90,120,151,181,212,243,273,304,334,365]
if (year% 4 = 0 and year%100!=0 and month>2) or (Year%400==0 and month>2): #闰年的二月是特殊的, one less condition: four years and a century does not leap or 400 years, There are also months to be greater than 2, between and OR
Days=day+list[month-1]+1
Else
DAYS=DAY+LIST[MONTH-1]
Print (days)
Else
Print (' Day error ')
Else
Print (' month error ')
Else
Print (' year error ')
'''
#方法二: The whole input month day, with the segmentation method to find the date of the split (), so that can be connected to the input date
'''
Date=input (' Enter month Day: yyyy-mm-dd: ')
y,m,d= (int (i) for I in Date.split ('-'))
Dth=0
MONTHS1=[0,31,60,91,121,152,182,213,244,274,305,335,366] #闰年
MONTHS2=[0,31,59,90,120,151,181,212,243,273,304,334,365] #平年
if ((y%4==0) and (y%100!=0)) or (y%100==0) and (y%400==0):
Dth=months1[m-1]+d
Else
Dth=months2[m-1]+d
Print (' Total days: ', Dth)
'''
#方法三: With a leap sign
"Year=int" (Input (' Input year: '))
Month=int (Input (' Input month: '))
Day=int (Input (' Input day: '))
Days=0
LIST=[0,31,59,90,120,151,181,212,243,273,304,334,365]
if (0<month<13):
Days=list[month-1]+day
Else
Print (' Data error ')
Leap=0
if (year% 4 = 0 and year%100!=0 and month>2) or (Year%400==0 and month>2): #闰年的二月是特殊的, one less condition: four years and a century does not leap or 400 years, There are also months to be greater than 2, between and OR
Leap=1
if (leap==1):
Print (days+1)
Else
Print (days)
'''
#方法四: Two list, judging is leap year or excepting, directly corresponding to the list on it
"" while (1):
Year=int (Input ("Year: \ n"))
Month=int (Input ("Month: \ n"))
Day=int (Input ("Day: \ n"))
MONTHS1=[0,31,60,91,121,152,182,213,244,274,305,335,366] #闰年
MONTHS2=[0,31,59,90,120,151,181,212,243,273,304,334,365] #平年
if ((year%4==0) and (year%100!=0)) or (year%100==0) and (year%400==0):
Dth=months1[month-1]+day
Else
Dth=months2[month-1]+day
Print (' Total days: ', Dth)
'''
#方法五: Using the time module
'''
Import time
Print (Time.strptime (' 2017-9-20 ', '%y-%m-%d ') [7]) #此处的大小写必须是这样的
'''
#方法六: Using the Calendar module
#!/usr/bin/env python
#-*-Coding:utf-8-*-
'''
Import Calendar
year = Int (input ("Year:"))
month = Int (input ("month:"))
day = Int (input (' Day: '))
Days = 0
If 0 < month <= 12:
_, Month_day = Calendar.monthrange (year, month)
If Day <= month_day:
For M in range (1, month):
_, Month_day = Calendar.monthrange (year, m)
Days = Month_day
Days = Day
Print (days)
Else
Print ("Input day Error")
Else
Print ("Input month Error")
'''
#方法七: Import Time Module
#! /usr/bin/env python
# Coding:utf-8

Import time
D=input ("Please enter the year, format such as xxxx-xx-xx:")
D=time.strptime (D, '%y-%m-%d '). Tm_yday
Print ("The {} of this year!". Format (d))