Question one hundred and six: Sum of Natural Numbers

[Plain] Description
 
 
Calculate S = 1 + (1 + 2) + (1 + 2 + 3) +... + (1 + 2 +... + N ). If N is known, write the program to find S.
 
 
Input
 
The first line has an integer T, indicating that there are T groups of test data. Line 2 ~ Row T + 1 has 1 integer N, 1 <= N <= 200.
 
Output
 
For each group of input data, the output line contains an integer, that is, the value of S.
 
Sample Input
 
 
2
1
200
 
Sample Output
 
 
1
1353400

Description

Calculate S = 1 + (1 + 2) + (1 + 2 + 3) +... + (1 + 2 +... + N ). If N is known, write the program to find S.

Input

The first line has an integer T, indicating that there are T groups of test data. Line 2 ~ Row T + 1 has 1 integer N, 1 <= N <= 200.

Output

For each group of input data, the output line contains an integer, that is, the value of S.

Sample Input

2
1
200

Sample Output

1
1353400
 

[Plain] # include <stdio. h>
 
Int SUM (int num );
 
Int main ()
{
Int I;
Int n;
Int num;
Int sum;

Scanf ("% d", & n );
 
While (n --)
{
Scanf ("% d", & num );
Sum = 0;
 
For (I = 1; I <= num; I ++)
{
Sum + = SUM (I );
}
 
Printf ("% d", sum );
 
If (n> 0)
{
Printf ("\ n ");
}
}
 
Return 0;
}
 
Int SUM (int num)
{
Int I;
Int sum = 0;
 
For (I = 1; I <= num; I ++)
{
Sum + = I;
}
 
Return sum;
}

# Include <stdio. h>

Int SUM (int num );

Int main ()
{
Int I;
Int n;
Int num;
Int sum;

Scanf ("% d", & n );

While (n --)
{
Scanf ("% d", & num );
Sum = 0;

For (I = 1; I <= num; I ++)
{
Sum + = SUM (I );
}

Printf ("% d", sum );

If (n> 0)
{
Printf ("\ n ");
}
}

Return 0;
}

Int SUM (int num)
{
Int I;
Int sum = 0;

For (I = 1; I <= num; I ++)
{
Sum + = I;
}

Return sum;
}