"Four Java Learning notes" Java Binary conversion

Tag: binary 16 binary images row signed valueof [] static conversion

Decimal turns into 16 binary:
integer.tohexstring (int i)
Decimal into octal
integer.tooctalstring (int i)
Decimal turns into binary
integer.tobinarystring (int i)
Hex turns into decimal
Integer.valueof ("FFFF", +). ToString ()
Octal into decimal
Integer.valueof ("876", 8). ToString ()
Binary goto Decimal
Integer.valueof ("0101", 2). ToString ()

Is there any way to directly convert the 2,8,16 into a 10-binary system?
Java.lang.Integer class
parseint (String s, int radix)
Resolves a string argument to a signed integer using the cardinality specified by the second argument.
Examples from JDK:
parseint ("0", ten) returns 0
parseint ("473", Ten) returns 473
parseint ("-0", returns 0)
parseint ("-ff", +) returns-255
parseint ("1100110", 2) returns 102
parseint ("2147483647", ten) returns 2147483647
parseint (" -2147483648", ten) returns-2147483648
parseint ("2147483648", ten) throws a NumberFormatException
parseint ("throws", a numberformatexception
parseint ("Kona", ten) throws a NumberFormatException
parseint ("Kona", returns 411787)

How the binary conversion is written (two, eight, 16) without algorithms
Integer.tobinarystring
Integer.tooctalstring
Integer.tohexstring


Example Two

public class test{
public static void Main (String args[]) {

int i=100;
String binstr=integer.tobinarystring (i);
String otcstr=integer.tooctalstring (i);
String hexstr=integer.tohexstring (i);
System.out.println (BINSTR);

}



Example Two
public class Teststringformat {
public static void Main (string[] args) {
if (Args.length = = 0) {
System.out.println ("Usage:java teststringformat <a number>");
System.exit (0);
}

Integer factor = integer.valueof (Args[0]);

String s;

s = String.Format ("%d", factor);
System.out.println (s);
s = String.Format ("%x", factor);
System.out.println (s);
s = String.Format ("%o", factor);
System.out.println (s);
}
}



Other methods:

Integer.tohexstring (your 10 binary number);
For example
String temp = integer.tohexstring (75);
Output TEMP is 4b



Enter a 10 binary number and convert it to 16 binary
Import java.io.*;
public class tohex{

public static void Main (String[]args) {

int input;//Store input data
Creating an instance of an input string
BufferedReader strin=new BufferedReader (New InputStreamReader (system.in));
System.out.println ("Please enter an integer:");
String X=null;
try{
X=strin.readline ();
}catch (IOException ex) {
Ex.printstacktrace ();
}
Input=integer.parseint (x);
System.out.println ("The number you entered is:" +input);//Output the number received from the keyboard


}
}

"Four Java Learning notes" Java Binary conversion