"Description of the problem" the flight brigade has several drivers from all over the world who specialize in one type of aircraft, each of which has two pilots and requires a positive driver and a co-pilot. For a variety of reasons, such as co-ordination, some pilots cannot fly on the same plane and ask how to match the driver to make the most of the flight. , assuming that there are 10 drivers, the V1,V2,...,V10 represents up to 10 drivers, of which V1,V2,V3,V4,V5 is the pilot, and V6,V7,V8,V9,V10 is the co-pilot. If a pilot and a co-pilot can fly on the same plane, on behalf of both of them a line between the two, two people can not fly with the aircraft, it is not connected. For example, V1 and V7 can fly on the same plane, while V1 and V8 do not. Please match the pilot to make the most of the aircraft sailing. Note: Because the driving division is strict, two pilots or two copilot cannot fly with each other. The input format input file has several lines
The first line, two integers n and N1, indicates a total of n pilots (2<=N<=100), including N1 pilots.
There are several lines below, each with 2 numbers, A, B. Indicates that both driver A and copilot B can fly on the same machine. Note: The pilot's number is before the driver's number is less than the pilot's number. Output format output file has one line
The first line, 1 integers, indicates the maximum number of aircraft to take off. Input Output Sample input file name: 10 5
1 7
2 6
2 10
3 7
4 8
5 9 Output File name: 4
"Analysis" began to do the network flow 24, this is the first problem, the Hungarian algorithm naked question, of course, can also network flow do, I wrote Hungary.
1#include <cstdio>2#include <cstdlib>3#include <cstring>4#include <iostream>5#include <algorithm>6#include <queue>7 using namespacestd;8 #defineMAXN 11009 Ten structnode One { A intX,y,next; -}T[MAXN];intLen; - intFIRST[MAXN]; the - voidInsintXinty) - { -t[++len].x=x;t[len].y=y; +t[len].next=first[x];first[x]=Len; - } + A intM,n; at - intMATCH[MAXN]; - BOOLCHW[MAXN]; - BOOLFfind (intx) - { - //printf ("%d\n", x); in for(intI=first[x];i;i=t[i].next)if(!Chw[t[i].y]) - { to inty=t[i].y; +chw[y]=1; - //printf ("%d\n", x); the if(!match[y]| |Ffind (Match[y])) * { $match[y]=x;Panax Notoginseng return 1; - } the } + return 0; A } the + intans; - voidSolve () $ { $memset (Match,0,sizeof(Match)); -ans=0; - for(intI=1; i<=n;i++) the { -memset (CHW,0,sizeof(CHW));Wuyi if(Ffind (i)) ans++; the } - } Wu - intMain () About { $scanf"%d%d",&m,&n); -len=0; -memset (First,0,sizeof(first)); - while(1) A { + intx, y; thescanf"%d%d",&x,&y); - if(x==-1&&y==-1) Break; $ ins (x, y); the } the solve (); theprintf"%d\n", ans); the /*for (int i=m+1;i<=n;i++) if (Match[i]) - { in printf ("%d%d\n", match[i],i); the }*/ the return 0; About}
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2016-11-04 08:40:05
"Network flow 24 questions" with pilots (pilot pairing scheme problem)