Description
The word "the" is the most common
Three-letter Word. It even
Shows up inside other words, such
As "other" and "mathematics".
Sometimes it hides, split between
Words, such as "not here."
Have your ever wondered what the
Most common words of lengths
Other than three is?
Your task is the following. You
would be given a text. In the This text,
Find the most common word of
Length one. If there is multiple
Such words, any one would do. Then
Count how many times the most
Common Word appears in the text. If It appears more than once, the output how many times it appears.
Then repeat the process with words of length 2, 3, and so on, until your reach such a length that
There is no longer any repeated word of that, length in the text.
Input
The input consists of a sequence of lines. The last line of input was empty and should not being processed.
Each line of input and than the last contains at least one and no more than one thousand uppercase
Letters and spaces. The spaces is irrelevant and should be ignored.
Output
For each line of input, output a sequence of lines, giving the number of repetitions of words of length
1, 2, 3, and so on. When your reach a length such that there is no repeated words of that length,
Output one blank line, does not output anything further for that input line, and move over to the next line
of input.
Note:remember the last line of the sample input and of the sample output must is blank.
Sample Input
The other mathematics isn't here
Aa
Sample Output
5
4
4
2
2
2
Test instructions
Given a text, find the length of 1, 2, 3, 4, 5 .... The maximum number of occurrences of a string, and the number of occurrences is not greater than 1.
Analysis
Direct for two times. Group by the length of the enumeration to find Max for the number of members of the group.
The code is as follows:
1#include <cstdio>2#include <cstdlib>3#include <cstring>4#include <iostream>5#include <algorithm>6#include <queue>7 using namespacestd;8 #defineMaxl 1000109 #defineINF 0XFFFFFFFTen One intL,len; A CharS[MAXL]; - intc[maxl],cl; - the intMymin (intXintY) {returnX<y?x:y;} - intMymax (intXintY) {returnX>y?x:y;} - - voidInit () + { -len=strlen (s); +Cl=0; A for(intI=0; i<len;i++)if(s[i]!=' ') atc[++cl]=s[i]-'A'+1; - } - - intSA[MAXL],RK[MAXL],Y[MAXL],WR[MAXL],RS[MAXL]; - voidGet_sa (intm) - { inmemcpy (Rk,c,sizeof(RK)); - for(intI=0; i<=m;i++) rs[i]=0; to for(intI=1; i<=cl;i++) rs[rk[i]]++; + for(intI=1; i<=m;i++) rs[i]+=rs[i-1]; - for(inti=cl;i>=1; i--) sa[rs[rk[i]]--]=i; the * intln=1, p=0; $ while(p<cl)Panax Notoginseng { - intk=0; the for(inti=cl-ln+1; i<=cl;i++) y[++k]=i; + for(intI=1; i<=cl;i++)if(SA[I]>LN) y[++k]=sa[i]-Ln; A for(intI=1; i<=cl;i++) wr[i]=Rk[y[i]]; the + for(intI=0; i<=m;i++) rs[i]=0; - for(intI=1; i<=cl;i++) rs[wr[i]]++; $ for(intI=1; i<=m;i++) rs[i]+=rs[i-1]; $ for(inti=cl;i>=1; i--) sa[rs[wr[i]]--]=Y[i]; - - for(intI=1; i<=cl;i++) wr[i]=Rk[i]; the for(inti=cl+1; i<=cl+ln;i++) wr[i]=0; -p=1, rk[sa[1]]=1;Wuyi for(intI=2; i<=cl;i++) the { - if(wr[sa[i]]!=wr[sa[i-1]]|| wr[sa[i]+ln]!=wr[sa[i-1]+LN]) p++; Wurk[sa[i]]=p; - } Aboutln*=2, m=p; $ } -sa[0]=rk[0]=0; - } - A intHEIGHT[MAXL]; + voidget_he () the { - intk=0; $ for(intI=1; i<=cl;i++)if(rk[i]!=1) the { the intj=sa[rk[i]-1]; the if(k) k--; the while(C[I+K]==C[J+K]&&I+K<=CL&&J+K<=CL) k++; -height[rk[i]]=K; in } the } the About voidFfind () the { the for(intI=1; i<=cl;i++)//Enumeration Length I the { + intCnt=0, ans=0; - for(intj=1; j<=cl;j++) the {Bayicnt++; the if(height[j+1]<i| | J==CL)//is the end of a group the { - if(cnt!=1) ans=Mymax (ans,cnt); -Cnt=0; the } the } the if(ans<=1) Break; theprintf"%d\n", ans); - } the } the the intMain ()94 { the BOOLok=0; the while(gets (s)) the {98 if(OK) printf ("\ n"); Aboutok=1; - init ();101Get_sa ( -);102 get_he ();103 Ffind ();104 } the return 0;106}
[UVA11855]
2016-07-19 16:31:07
"POJ11855" buzzwords (suffix array)