Regular Expression Matching && 44. Wildcard Matching

Source: Internet
Author: User

Ten. Regular Expression Matching

Implement regular expression matching with support for ‘.‘ and ‘*‘ .

‘.‘ Matches any single character. ' * ' Matches zero or more of the preceding element. The matching should cover the entire input string (not partial). The function prototype should be:bool IsMatch (const char *s, const char *p) Some examples:ismatch ("AA", "a") →falseismatch ( "AA", "AA") →trueismatch ("AAA", "AA") →falseismatch ("AA", "A *") →trueismatch ("AA", ". *") →trueismatch ("AB", ". *") →true IsMatch ("AaB", "C*a*b") →true

 Public classSolution { Public BooleanIsMatch (String s, String p) {returnIsMatch (S, 0, p, 0); }            Private BooleanIsMatch (String S,intSi, String p,intpi) {        if(PI = =p.length ())returnSi = =s.length (); CharPcurrent =P.charat (PI); if(Pi+1<p.length () && p.charat (pi+1) = = ' * ')//if followed by star        {            if(IsMatch (S, Si, P, pi+2))//Skip the first star part.                return true; if(Si<s.length () && (S.charat (si) = = Pcurrent | | pcurrent = = '. ') && IsMatch (S, si+1, P, pi)) return true; return false; }        Else //Match single character        {            if(SI = =s.length ())return false;//if S is already at the end.            if(Pcurrent! = S.charat (SI) && pcurrent! = '. ')                return false;//cannot find the match in S.            returnIsMatch (S, si+1, p, pi+1); }    }}

Regular Expression Matching && 44. Wildcard Matching

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