Regular Expressions-match URLs in PHP strings

Demand:

客户端传过来一段字符串，需要从字符串中匹配出所有的url，包括域名或IP后面的参数（含端口）

URL Example:

http://127.0.0.1/metinfo/img/img.php?class1=1&serch_sql=%201=if%28ascii%28substr%28user%28%29,1,1%29%29=114,1,2%29%23或者http://www.baidu.com/metinfo/img/img.php?class1=1&serch_sql=%201=if%28ascii%28substr%28user%28%29,1,1%29%29=114,1,2%29%23

Of course, simple URLs are also to be matched.
Solving the regular

Reply content:

Demand:

客户端传过来一段字符串，需要从字符串中匹配出所有的url，包括域名或IP后面的参数（含端口）

URL Example:

http://127.0.0.1/metinfo/img/img.php?class1=1&serch_sql=%201=if%28ascii%28substr%28user%28%29,1,1%29%29=114,1,2%29%23或者http://www.baidu.com/metinfo/img/img.php?class1=1&serch_sql=%201=if%28ascii%28substr%28user%28%29,1,1%29%29=114,1,2%29%23

Of course, simple URLs are also to be matched.
Solving the regular

Match all URLs with a fairly broad regular, such as

https?:\/\/\S+

And then take the function for this heap of URLs in turn parse_url

^(http|https|ftp)\://[a-zA-Z0-9\-\.]+\.[a-zA-Z]{2,3}(:[a-zA-Z0-9]*)?/?([a-zA-Z0-9\-\._\?\,\'/\\\+&%\$#\=~])*$http://regexlib.com/Search.aspx?k=url&c=-1&m=5&ps=20

Java probably wrote this.

String str = "接收到的字符串"String regex = "(http:|https:)//[^[A-Za-z0-9,:\\._\\?%&+\\-=/#]]*";        Pattern pattern = Pattern.compile(regex);        Matcher matcher = pattern.matcher(str);        while (matcher.find()) {            String url=matcher.group();            System.out.println(url);        }

The following string passes the test.

String str="http://127.0.0.1:6666/ " +                "https://www.baidu.com/ " +                "http://127.0.0.1/metinfo/img/img.php?class1=1&serch_sql=%201=if%28ascii%28substr%28user%28%29,1,1%29%29=114,1,2%29%23\n" +                "或者\n" +                "哈哈http://www.baidu.com:85676/metinfo/img/img.php?class1=1&serch_sql=%201=if%28ascii%28substr%28user%28%29,1,1%29%29=114,1,2%29%23 6666都是对的";

输出

http://127.0.0.1:6666/https://www.baidu.com/http://127.0.0.1/metinfo/img/img.php?class1=1&serch_sql=%201=if%28ascii%28substr%28user%28%29,1,1%29%29=114,1,2%29%23http://www.baidu.com:85676/metinfo/img/img.php?class1=1&serch_sql=%201=if%28ascii%28substr%28user%28%29,1,1%29%29=114,1,2%29%23

What, you asked for PHP? Sorry, I do not PHP ...
Just the same, you have to move your head.

