Ruby:count unique elements and their occurences in an array

Is there a method in Ruby that takes an array, and counts all unique elements and their occurrences and passes them back a S a hash?

For example

  [' A ',' A ',' A ',' A ',' B ',' B ',' C '].Method> {' A ' = 4, ' B ' = 2, ' C ' = 1}

Something like that.

 [  ' a '    ' a '    ' A '    ' a '    ' B '    ' B '    ' C '  ].  group_by  {|  e  |   e    map  {|  k    v  |    [ k  ,   v   length   to_h  

src= [' A ',' A ',' A ',' A ',' B ',' B ',' C ']Hash[src.group_by{ |x|x}.Map{ |k,v| [k,v.length] }]
counts= Hash.New(0)[' A ',' A ',' A ',' A ',' B ',' B ',' C ']. each{ |name|counts[name] += 1 }Counts = {"A" =>4, "B" =>2, "C" =>1}


[' A ',' A ',' A ',' A ',' B ',' B ',' C '].Each_with_object(Hash.New(0)) { |L,o|o[L] += 1 }

            
The easiest readable for me:
src= [' A ',' A ',' A ',' A ',' B ',' B ',' C ']src.group_by(&:to_s).to_a.Map{ |a| [a[0],a[1].Count] }.To_h
Or here are another solution with reduce method:
src.reduce({}) { |b, a| b.merge({a => (b[a] || 0) + 1}) }
Pre
src.reduce(Hash.new(0)) { |b, a| b.merge({a => b[a] + 1}) }
    

Ruby:count unique elements and their occurences in an array