Shell _linux The shell based on the date, month, and week of the Year code

Known three time variables:
time1= "Fri Aug 23 11:35:21"
Time2= "Mon Sep 2 16:18:09"
Time3= "Tue Sep 3 16:06:33"
Given that these three times can be determined to occur in 2011-2013, how quickly to determine what year it is?

Want to output:
time1= "2013/8/23 11:35:21"
time2= "2013/9/2 16:18:09"
time3= "2013/9/3 16:06:33"

#!/bin/bash
time1= "Fri Aug 11:35:21" time2= "Mon
Sep 2 16:18:09" time3= "
Tue Sep 3 16:06:33"
time4= " Sun Dec 2 16:06:34 "for
((i=1;i<=4;i++)), Do for
  ((j=2011;j<=2013;j++)), do
    str=$ (eval echo \ $time $i)
    week_day=$ (date-d "${str:0:10} $j ${str:10}" "+%a")
    if ["${str:0:3}" = = $WEEK _day]; then
      echo time$i=\ "$ ( Date-d "${str:0:10} $j ${str:10}" "+%y/%m/%d%T") \ "
      # break
    fi
  done