Shell Script---View the number of rows in the log file that contain some strings every few hours

In the Linux production environment, there are the following such a common operations need to work.

Every once in a while, such as two hours, the log file to generate the log per second (this is assumed to be testfile.out, the absolute path is/home/panlm/shellpra/ Testfile.out) is an operation that prints the lines of the log containing certain strings separately and puts them back in a file (where the file is assumed to be out.log). These strings that need to be matched can be represented in this way by "0x216000ab" where AB is a continuous integer of 01 to 18.

There are two main steps to achieving such a requirement

One, through the shell script, the implementation of the target log to meet the requirements of the line output to a new file.

Ii. deploying the script through crontab run every two hours

The contents of Testfile.out are as follows

1231 0x21600001

32343 0x21600002

23123 0x21600003

42232 0x21600004

22323jkshdkfkadlfdsd

FJSDKDJF 0x21600018

SDAFD 0x21600043

Sajdkfjjjjls

First, the Shell script implementation

Script name is get.sh

#!/bin/bash

#define VARs

Log_file= "/home/panlm/shellpra/testfile.out

Sum=1

#将字符串 "0x216000ab" is divided into two parts, a fixed part of the string, part of a variable integer part

str1= "0x216000"

Str2= "0x2160000"

For i in {1..18}

Do

If ["$sum"-lt 10]

Then

#将两个字符串合并成一个字符串

Str=${str2}${sum}

In #将满足结果的行数输出到结果文件out. log

grep $str $Log _file |cat >> out.log

Let "sum= $sum +1"

Else

Str=${str1}${sum}

In #将满足结果的行数输出到结果文件out. log

grep $str $Log _file |cat >> out.log

Let "sum= $sum +1"

Fi

Done

After executing the script, the file Out.log contents are as follows

1231 0x21600001

32343 0x21600002

23123 0x21600003

42232 0x21600004

FJSDKDJF 0x21600018

Second, every two hours to execute the script

0 */2 * * */home/panlm/shellpra/get.sh

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Shell Script---View the number of rows in the log file that contain some strings every few hours