Simple Date Class

Source: Internet
Author: User

"Task Requirements"

1. Implementation: Date + days = date;

2. Implementation: Date-days = date;

3. Implementation: Date-date = number of days;


"code implementation"

#include  <iostream>using namespace std;class Date{friend ostream&  operator<< (ostream& os ,const date& d);//friend Public:date (int year = &NBSP;1900,&NBSP;INT&NBSP;MONTH&NBSP;=&NBSP;1,&NBSP;INT&NBSP;DAY&NBSP;=&NBSP;1)//constructor: _year (year), _month (month ), _day (day) {if  (Isinvaliddate ())  //processing Invalid date {_year = 1900;_month = 1;_day =  1;}} Date (CONST&NBSP;DATE&AMP;&NBSP;D)//copy constructor {_year = d._year;_month = d._month;_day =  d._day;} Date& operator= (const date& d)  //assignment operator overload {if (this != &d) {this->_ Year = d._year;this->_month = d._month;this->_day = d._day;} Return *this;} public:/* determine if the date is valid */bool isinvaliddate () {if  ((_year<1900) | | ((_month < 1)  | |   (_month > 12)) | | ((_day < 1)  | |  _day > getmonthday ())) {Return true;} Return false;} /* Determine if _year is a leap year */bool leapyear () {return  (0 == _year %4 &&0 != _ YEAR&NBSP;%&NBSP;100) | | (0 == _year % 400);} /* Get _month How many days */int getmonthday () {int days[13] = {0, 31, 28, 31, 30,  31, 30, 31, 31, 30, 31, 30, 31};if (LeapYear ()) {Days[2] += 1 ;} Return days[_month];} /* Determine if two dates are equal */bool operator== (const date& d)     {return  (this-> _year == d._year)  &&  (this->_month == d._month)  &&  (This->_day == d._day);     }bool operator!= (const Date& d)     {return ! ( *THIS&NBSP;==&NBSP;D)     }/* judge the size relationship between *this and D */bool operator> (const Date& &NBSP;D)     {if (_year > d._year) {REturn true;} Else if (_year == d._year) {if (_month > d._month) {return true;} Else if (_month == d._month) {if (_day > d._day) {return true;}}} return false;    }bool operator< (const date& d) {return ! ( *THIS&NBSP;&GT;&NBSP;D);} bool operator>= (Const date& d) {return  ((*this > d) | | (*this == d));} bool operator<= (Const date& d) {return  ((*this < d) | | (*this == d));} Public:void getnowdate ()//Get new Date {while (_day <= 0) {if  (_month == 1) {_month  = 12;_year -= 1; }else {_month -= 1;} _day += getmonthday ();} while (_day > getmonthday ()) {_day -= getmonthday ();  if (_month == 12) {_ month = 1;_year += 1;} else{_month += 1;}  }}date operator+ (INT&NBsp;day)//date  +  days  = Date {int days[13] = {0, 31, 28, 31, 30, &NBSP;31,&NBSP;30,&NBSP;31,&NBSP;31,&NBSP;30,&NBSP;31,&NBSP;30,&NBSP;31};D ate d (*this);d. _day +=  day;d.getnowdate (); return d;} date operator-(Int day)//date  -  days  = date {int days[13] = {0, 31,  28,&NBSP;31,&NBSP;30,&NBSP;31,&NBSP;30,&NBSP;31,&NBSP;31,&NBSP;30,&NBSP;31,&NBSP;30,&NBSP;31};D ate d (* This);d. _day -= day;d.getnowdate (); return d;} date& operator+= (int day) {_day += day;this->getnowdate (); return *this;} date& operator-= (int day) {_day -= day;this->getnowdate (); return *this;} int operator-(const date& d)  //date-date  = days {int day = 0;if (*this &NBSP;&GT;&NBSP;D) {date d1 = *this;*this = d;} while (*this != d) {*this += 1;day++;} Return day;} private:int  _year;int _month;int _day;};o stream& operator<< (ostream& os ,const date& d)   //output operator overloading    {os << d._year <<  "-"  << d._month < <  "-" &NBSP;&LT;&LT;D._DAY&NBSP;&LT;&LT;&NBSP;ENDL;&NBSP;&NBSP;&NBSP;&NBSP;RETURN&NBSP;OS;} Int main () {  date d (2016, 3, 2);D ate d1 (1995, 7, 14); Int ret  = d-d1;cout <<  "by the end of "       << d << "you have already lived for "       << ret <<  " days"  << endl;system ("pause"); return 0;}

Results:

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This article is from the "Pzd Chuan Feng" blog, please make sure to keep this source http://xujiafan.blog.51cto.com/10778767/1746869

Simple Date Class

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