Simulate a cube that can be rotated in C ++ (1)

I have been playing the cube, and I have always wanted to program it.

 

I finally started today ~

 

Ideas:

1. divide the cube into six slices (each cube is a cube of 1 × 3 × 3) and use a 5 × 5 char array, W, Y, B, G, respectively, o, r fill array with six letters to represent various colors

Example: [] [B] [B] [B] [] B-BLUE O-orange w-White R-Red G-green

[O] [W] [W] [W] [R]

[O] [W] [W] [W] [R]

[O] [W] [W] [W] [R]

[] [G] [g] [g] []

 

(The so-called "1*3*3" is the area marked by the lawn light)

2. Create a piece class and add the rotation attributes of the slices: 90 degrees clockwise, 90 degrees clockwise, and 180 degrees Celsius.

 

3. Create a cube class. There are 6 pieces in the class that correspond to 6 of the cube,

Create Function 1 to Control the effect of each slice rotation on other slice.

Create Function 2 and read user commands to control cube rotation (such as U, L, R)

 

4. Call the C ++ graphics library to visualize the cube class. (There is no contact with this part)

 

 

 

Code of the slice:

 // Piece. h-cube Category </P> <p> # include <iostream. h> <br/> # define M 5 <br/> // ======================== ===============================< br/> class piece <br/> {<br/> PRIVATE: <br/> char a [m] [m]; <br/> Public: <br/> piece (char X [m] [m]) // constructor introduces the array in the main program for initialization <br/>{< br/> for (INT I = 0; I <m; I ++) <br/> for (Int J = 0; j <m; j ++) <br/> A [I] [J] = x [I] [J]; <br/>}</P> <p> void cirni (void) // counter-clockwise rotation function <br/>{< br/> int B [m] [m]; <br/> int I, j; <br/> for (I = 0; I <m; I ++) <br/> for (j = 0; j <m; j ++) <br/> B [M-1-j] [I] = A [I] [J]; // convert array a to array B <br/> for (I = 0; I <m; I ++) <br/> for (j = 0; j <m; j ++) <br/> A [I] [J] = B [I] [J]; <br/>}</P> <p> void cirsh (void) // clockwise rotation function <br/>{< br/> int B [m] [m]; <br/> int I, j; <br/> for (I = 0; I <m; I ++) <br/> for (j = 0; j <m; j ++) <br/> B [J] [M-i-1] = A [I] [J]; <br/> for (I = 0; I <m; I ++) <br/> for (j = 0; j <m; j ++) <br/> A [I] [J] = B [I] [J]; <br/>}</P> <p> void cirnipp (void) // 180 degree rotation function <br/>{< br/> int B [m] [m]; <br/> int I, J; <br/> for (I = 0; I <m; I ++) <br/> for (j = 0; j <m; j ++) <br/> B [M-i-1] [M-j-1] = A [I] [J]; <br/> for (I = 0; I <m; I ++) <br/> for (j = 0; j <m; j ++) <br/> A [I] [J] = B [I] [J]; <br/>}</P> <p> void show (void) // print the array <br/> {<br/> for (INT I = 0; I <m; I ++) <br/> {<br/> for (Int J = 0; j <m; j ++) cout <A [I] [J] <""; <br/> cout <Endl; <br/>}</P> <p> };

 

The idea of this header file comes from here: http://zhidao.baidu.com/question/165615023.html? SI = 1

 

Core Statement:

B [M-1-j] [I] = A [I] [J]; clockwise rotation

B [J] [M-i-1] = A [I] [J]; clockwise rotation

B [M-i-1] [M-j-1] = A [I] [J]; 180 degree rotation