Simulate time-based conversion and output current year calendar

This is a friend entrusted me to play, do not belong to ACM, but feel very interesting, so put here, the topic has two requirements, output when the 1 years January 1 to the year before the month before the 1th number of days separated, and output this day is the days of the week, and then output this year in the format of 12 months of the Gregorian calendar.

is a very simple simulation, is a little bit of trouble and small details to note, the following is the code:

#include <iostream>#include<cstdio>#include<cstring>using namespacestd;structnode{intY,m,d,day;}; Node start;voidinit () {Start.y=1; START.M=1; START.D=1; Start.day=1;}BOOLIs_leap (intYear ) {    if(year% -==0|| (year%4==0&&year% -!=0))return true; Else return false;}intDay_of_month (intYearintm) {    if(m==1|| m==3|| m==5|| m==7|| m==8|| m==Ten|| m== A)return  to; if(m==2)    {        if(Is_leap (year))return  in; return  -; }    return  -;} Node tmp;intgetday (Node now) {tmp=start; intAns =0; BOOLFlag =false;  while(tmp.y<=now.y) { while(tmp.m <= A)        {             while(TMP.D <=Day_of_month (tmp.y,tmp.m)) {                if(tmp.y==now.y&&tmp.m==now.m&&tmp.d==now.d) {flag=true;  Break; } TMP.D++; Tmp.day++; if(tmp.day==8) {Tmp.day=1; }                ///cout<< "Year Month Day D:" <<tmp.y<< "<<tmp.m<<" "<<tmp.d<<" "<< tmp.day<<endl;ans++;            }            if(flag) Break; TMP.D=1; TMP.M++; }        if(flag) Break; TMP.M=1; TMP.Y++; }    returnans;}intMain () {intnowyear; scanf ("%d",&nowyear);    Init ();    Node now; Now.y=nowyear; NOW.D=1; intfirstday[ -]; intallday[ -];  for(inti =1; I <= A; i++) {now.m=i; intres =Getday (now); printf ("%d days%d months, 1th .", Nowyear,i,res); printf ("This is the day of the week%d\n", Tmp.day); Firstday[i]=Tmp.day; Allday[i]=Day_of_month (nowyear,i); Puts (""); }     for(inti =1; I <= A; i++) {printf ("%d months \ n", i); printf ("-----------------------\ n"); ///printf ("7 1 2 3 4 5 6\n");printf"Day 123456 \ n"); intKey =Firstday[i]; ///cout<< "key =" <<key<<endl;if (Key< 7)        {             for(intj =1; J <= key;j++) cout<<"   "; }        inttot =1, K1 = key==7?7:7-key,k0 =0; BOOLMark =false;  while(Tot <=Allday[i]) {printf ("%3d", tot); K0++; Tot++; if(K0==K1 &&!)Mark) {Puts (""); K0=0; Mark=true; }            if(mark&&k0==7) {puts (""); K0=0; }} puts (""); }    return 0;}

Simulate time-based conversion and output current year calendar