Small issues with two-dimensional arrays

Source: Internet
Author: User

Int main (INT argc, char * argv [])
Int A [2] [3] = {0, 8, 2, 3, 4, 5 };
Int ** P;
P = (INT **);
Cout <* (p + 1) <Endl;
Return 0;
What is output?


We all know that,

If it is ** (a + 1), the output time is 3.

If it is * (* A + 1), the output time is 8

What about P?

I ran it on vs2005.
00000008 output
If * (p + 2), the output is 00000002


Here it should be like this: for a [2] [3], a itself is a pointer array, which contains two pointers pointing to two int [3] arrays respectively.
However, when P obtains the pointer value of A, it thinks that it points to the memory as a pointer array. At this time, it points to the memory, which actually stores
For p + 1, it moves one digit backward, pointing to 8, and thinks it is a pointer, so the output is 00000008

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