# Solution method and code implementation of editing distance

Source: Internet
Author: User
Tags first string min

For the editing distance, refer to the following URL: http://www.cnblogs.com/biyeymyhjob/archive/2012/09/28/2707343.html

The editing distance is a string at least how many steps can be changed to another string, including: Delete, add, modify. Delete and add is reflexive, i.e. edit (i-1,j) +1 or edit (i,j-1) +1. The following add 1 is the cost of modifying and adding the operation, the modification is edit (i-1,j-1) + (0|1). The next add 0 or add 1 is to see the first string of the I-character and the second string of the J-character is equal, equality is no need to modify, so add 0, not equal to the need for one-step modification, need to add 1.

The specific code is

```public class Bijijuli {public

static void Main (string[] args) {
System.out.println (editinstance ("Ergabd", "ABC "));
}

private static int min (int a,int b) {
return a < b a:b;
}

private static int Editinstance (string str1, String str2) {

int max1 = Str1.length ();
int max2 = Str2.length ();

int[][] Matrix = new Int[max1+1][max2+1];

for (int i=0;i<max1+1;i++) {
matrix[i][0] = i;
}
for (int i = 0;i<max2+1;i++) {
matrix[0][i] = i;
}

for (int i=1;i<max1+1;i++) {for
(int j=1;j<max2+1;j++) {
int d = 1;
int temp = min (matrix[i-1][j]+1,matrix[i][j-1]+1);
if (str1.substring (i-1, i). Equals (Str2.substring (j-1,j))) {
d = 0;
}
Matrix[i][j] = min (temp,matrix[i-1][j-1]+d);
}
}
return MATRIX[MAX1][MAX2];
}
}
```

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