# Solve Joseph's problem through a circular linked list-PHP source code

Source: Internet
Author: User
Php code for solving the Joseph problem using a ring linked list:

```// Circular linked list/* solve the Joseph problem and set the number of persons starting from 1-N according to the number of individuals starting from k to report the number from 1, and report the number to the person from m. His next digit starts counting from 1, and the person counting to M goes out again, and so on until all the people come out of the column and find the column order, and the last column number */header ("content-type: text/html; charset = utf-8"); class Child {public \$ no; public \$ next = null; public function _ construct (\$ no) {\$ this-> no = \$ no ;}} function addChild (& \$ first, \$ n) {\$ cur = null; for (\$ I = 0; \$ I <= \$ n-1; \$ I ++) {\$ child = new child (\$ I + 1); if (\$ I = 0) {\$ first = \$ child; \$ first-> next = \$ child; \$ cur = \$ first;} else {\$ cur-> next = \$ child; \$ child-> next = \$ fi Rst; \$ cur = \$ cur-> next ;}} function showChild (\$ first) {\$ cur = \$ first; while (\$ cur-> next! = \$ First) {echo \$ cur-> no; \$ cur = \$ cur-> next;} echo \$ cur-> no;} function countChild (\$ first, \$ m, \$ k) {\$ tail = \$ first; // consider starting from the first few children for (\$ I = 0; \$ I <M-1; \$ I ++) {\$ tail = \$ tail-> next;} while (\$ tail-> next! = \$ Tail) // remove to the linked list only one element until {for (\$ I = 0; \$ I <\$ K-1; \$ I ++) {\$ cur = \$ tail; // record his previous position \$ tail = \$ tail-> next;} echo 'column output '. \$ tail-> no; \$ cur-> next = \$ tail-> next; \$ tail = \$ tail-> next;} echo '123 '. \$ tail-> no;} addChild (\$ first, 10); showChild (\$ first); echo"
"; CountChild (\$ first, 2, 3); // count the number of the second child to three```
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