Some common functions (vb) for processing datetime in ASP. NET)

Uses the Timespan method to subtract a certain number of days
Function Date1 ()
Dim NewTime as DateTime
NewTime = DateTime. Now. Subtract (New TimeSpan (7, 0, 0, 0 ))
NewTime = NewTime. Format ("MM/dd/yyyy", DateTimeFormatInfo)
Response. write (NewTime)
End Function

Uses the AddDays method to subtract X number of days
Public Function Date2 ()
Dim NewTime as DateTime
NewTime = DateTime. Now. AddDays (-7)
Dim s as string = NewTime
Return s
End Function

Thanks to Paul czywcstmski for this idea
This probably (In My opinion) Offers the most flexibility found so far
Change where the MM/dd/yyyy to whatever
Response. write (System. String. Format ("{0: d}", NewTime ))
Wocould return just the name of the Day
Function Date3 ()
Dim NewTime as DateTime = now. addDays (-7)
Response. write (System. String. Format ("{0: MM/dd/yyyy}", NewTime ))
End Function

Function Date4 ()
Dim NewTime as DateTime
NewTime = now. addDays (-7)
Return NewTime. ToString ()
End Function

Uses the toLongTimeString method
Public Function Date5 ()
Dim NewTime as DateTime
NewTime = Now ()
Return newtime. toLongTimeString ()
End Function

Uses the toShortTimeString method
Public Function Date6 ()
Dim NewTime as DateTime
NewTime = Now ()
Return newtime. tow.timestring ()
End Function

Uses the toLongDateString method
Public Function Date7 ()
Dim NewTime as DateTime
NewTime = Now ()
Return newtime. toLongDateString ()
End Function

Uses the toShortDateString method
Public Function Date8 ()
Dim NewTime as DateTime
NewTime = Now ()
Return newtime. tow.datestring ()
End Function

Uses FormatDateTime function General format
Function Date9 ()
Dim NewTime as DateTime
NewTime = DateTime. Now. Subtract (New TimeSpan (7, 0, 0, 0 ))
Return formatdatetime (NewTime, 0)
End Function

Uses FormatDateTime function LongDate format
Function Date10 ()
Dim NewTime as DateTime
NewTime = DateTime. Now. Subtract (New TimeSpan (7, 0, 0, 0 ))
Return formatdatetime (NewTime, 1)
End Function

Uses FormatDateTime function Updated Date format
Function Date11 ()
Dim NewTime as DateTime
NewTime = DateTime. Now. Subtract (New TimeSpan (7, 0, 0, 0 ))
Return formatdatetime (NewTime, 2)
End Function

Uses FormatDateTime function LongTime format
Function Date12 ()
Dim NewTime as DateTime
NewTime = DateTime. Now. Subtract (New TimeSpan (7, 0, 0, 0 ))
Return formatdatetime (NewTime, 3)
End Function

Uses FormatDateTime function processing time format
Function Date13 ()
Dim NewTime as DateTime
NewTime = DateTime. Now. Subtract (New TimeSpan (7, 0, 0, 0 ))
Return formatdatetime (NewTime, 4)
End Function

Bring Back just the name of the Day
Function Date14 ()
Dim NewTime as DateTime = now. addDays (-7)
Dim s as string
S = (System. String. Format ("{0: dddd}", NewTime ))
Return s
End Function

Returns the Integer of what day of week
Function Date15 ()
Dim MyDate as DateTime
Dim MyWeekDay as Integer
MyDate = Now. AddDays (-5)
MyWeekDay = Weekday (MyDate)
Return MyWeekDay
End Function

Returns the Month Integer
Function Date16 ()
Dim MyDate as DateTime
Dim MyMonth as Integer
MyDate = Now. AddDays (-5)
MyMonth = Month (MyDate)
Return MyMonth
End Function

Returns just a formatted string
This method provides just formatting
Very flexible with not a lot of code
Function Date17 ()
Dim MyDate as String
MyDate = Format (Now (), "yyyy ")
Return MyDate
End Function
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