Spoj_4487
In fact, this question is similar to gss1, but due to the addition and deletion operations, we can't solve it with the line segment tree. Therefore, we can maintain a splay to implement these operations.
But what I wrote at the beginningProgramIt's always TLE, but compared with some online AC programs, we found that there are only two very different points. One is that they use struct, and the other is that they use pointers. When I was puzzled, I used several arrays to write a struct like an AC program, as shown below:
StructSplay {IntLeft, right, pre, size, sum, MC, key, LC, RC;# DefineLeft (x) SP [X]. Left# DefineRight (x) SP [X]. Right# DefinePre (x) SP [X]. Pre# DefineSize (x) SP [X]. Size# DefineSum (x) SP [X]. Sum# DefineMC (x) SP [X]. MC# DefineKey (x) SP [X]. Key# DefineLC (x) SP [X]. LC# DefineRC (x) SP [X]. RC} SP [maxd];
Nima ...... Actually ac ......
I don't know if this is an underlying optimization ...... Colleagues from TLE may wish to try writing a struct ......
# Include <stdio. h> # Include < String . H> # Include <Cstdlib> # Define Maxd 200010 # Define INF 0x3f3f3f Int N, t, a [maxd], node; Struct Splay { Int Left, right, pre, size, sum, MC, key, LC, RC; # Define Left (x) SP [X]. Left # Define Right (x) SP [X]. Right # Define Pre (x) SP [X]. Pre # Define Size (x) SP [X]. Size # Define Sum (x) SP [X]. Sum # Define MC (x) SP [X]. MC # Define Key (x) SP [X]. Key # Define LC (x) SP [X]. LC # Define RC (x) SP [X]. RC } SP [maxd]; Int Max (Int X, Int Y ){ Return X> Y? X: Y ;} Void Newnode ( Int & Cur, Int V) {cur = ++ Node; size (cur) = 1 ; Key (cur) = Sum (cur) = MC (cur) = Lc (cur) = RC (cur) = V; left (cur) = Right (cur) =0 ;} Void Update ( Int Cur ){ Int Ls = left (cur), RS = Right (cur); size (cur) = Size (LS) + size (RS) + 1 ; Sum (cur) = Sum (LS) + sum (RS) + Key (cur); MC (cur) = Max (RC (LS ), 0 ) + Key (cur) + max (LC (RS ), 0 ); MC (cur) =Max (MC (cur), max (MC (LS), MC (RS); LC (cur) = Max (LC (LS), sum (LS) + key (cur) + max (LC (RS ), 0 ); RC (cur) = Max (RC (RS), sum (RS) + key (cur) + max (RC (LS ), 0 ));} Void Leftrotate ( Int Cur ){ Int K = right (cur), fa = Pre (cur); Right (cur) = Left (k); Pre (right (cur )) = Cur; left (k) = Cur; Pre (cur) = K; Pre (k) = Fa; right (FA) = Cur? Right (FA) = K: Left (FA) = K; Update (cur );} Void Rightrotate ( Int Cur ){ Int K = left (cur), fa = Pre (cur); left (cur) = Right (k); Pre (left (cur )) = Cur; right (k) = Cur; Pre (cur) = K; Pre (k) = Fa; right (FA) = Cur? Right (FA) = K: Left (FA) = K; Update (cur );} Void Build ( Int & Cur, Int X, Int Y, Int FA ){ Int Mid = (x + y)> 1 ; Newnode (cur, a [Mid]); Pre (cur) =Fa; If (X = Y) Return ; If (X < Mid) Build (left (cur), X, mid - 1 , Cur ); If (Mid < Y) Build (right (cur), mid + 1 , Y, cur); Update (cur );} Void Splay (Int X, Int Goal ){ Int Y, Z; For (;;){ If (Y = pre (x) = Goal) Break ; If (Z = pre (y) = Goal) Right (y) = X? Leftrotate (y): rightrotate (y ); Else { If (Right (z) = Y) Right (y) = X? (Leftrotate (z), leftrotate (y): (rightrotate (Y), leftrotate (z )); Else Left (y) = X? (Rightrotate (z), rightrotate (y): (leftrotate (Y), rightrotate (z ));}} If (Goal = 0 ) T = X; Update (x );} Void Rotateto ( Int K, Int Goal ){ Int Cur = T, N; For (;) {N = Size (left (cur) + 1 ; If (N = K) Break ; If (K < N) cur = Left (cur ); Else K -= N, cur = Right (cur);} splay (cur, goal );} Void Init (){ Int I; For (I = 1 ; I <= N; I ++ ) Scanf ( " % D " ,& A [I]); Node = Size ( 0 ) = Sum ( 0 ) = 0 ; MC ( 0 ) = Lc ( 0 ) = RC ( 0 ) =- INF; newnode (t, 0 ), Newnode (right (t ), 0 ); Pre (right (t )) = T; Key (t) = Key (right (t) = 0 ; If (N) Build (left (right (t )), 1 , N, right (t); Update (right (t), update (t );} Void Delete ( Int X) {rotateto (X, 0 ), Rotateto (x + 2 , T); left (right (t )) = 0 ; Update (right (t), update (t );} Void Insert ( Int X, Int Y) {rotateto (X, 0 ), Rotateto (x + 1 , T); newnode (left (right (t), Y); Pre (node) = Right (t); Update (right (t), update (t );} Void Replace ( Int X, Int Y) {rotateto (x + 1 ,0 ); Key (t) = Y; Update (t );} Void Query ( Int X, Int Y) {rotateto (X, 0 ), Rotateto (Y + 2 , T); printf ( " % D \ n " , MC (left (right (t ))));} Void Solve (){ Int I, Q, X, Y; Char OP [ 5 ]; Scanf ( " % D " ,& Q ); For (I = 0 ; I <q; I ++ ) {Scanf ( " % S " , OP ); If (OP [ 0 ] = ' D ' ) {Scanf ( " % D " ,& X); Delete (x );} Else {Scanf ( " % D " , & X ,& Y ); If (OP [ 0 ] = ' I ' ) Insert (x, y ); Else If (OP [ 0 ] = ' R ' ) Replace (x, y ); Else Query (x, y );}}} Int Main (){ While (Scanf ( " % D " , & N) = 1 ) {Init (); solve ();} Return 0 ;}