Springmvc the date method for receiving the string and the return string type date to the front end

Date type data sent over the front end cannot receive

	<mvc:annotation-driven conversion-service= "Conversionservice"/>   <!--The original wording injected the time parameter converter parameter string Convert to date type  -->
	
	<bean id= "Conversionservice" class= " Org.springframework.format.support.FormattingConversionServiceFactoryBean "> 
		<property name=" Converters ">
			<list>
				<bean class=" Com.bim.revit.controller.common.DateConverter "/>
			</list>
		</property>
	</bean>

And then I found a single date matching method.

@DateTimeFormat (pattern= "Yyyy-mm-dd HH:mm:ss")

It's okay.

@JsonFormat (pattern= "Yyyy-mm-dd HH:mm:ss", timezone = "gmt+8")

Returns the time of the front-end string format

Reference

  When querying the database, the date type returned is Java.sql.date, The browser is set to Java.util.date in a custom node object, but the sql.date loses information about the time, only the date, the SQL is queried as a string, and the resulting string is converted to Util.date, when the browser displays a long timestamp;
    Workaround: Database query result is string, converted to Util.date added to node object, node object's definition of date type variable, add annotation:
@DateTimeFormat (pattern= " Yyyy-mm-dd HH:mm:ss ")
@JsonFormat (pattern=" Yyyy-mm-dd HH:mm:ss ", timezone =" gmt+8 ")
    Spring formats the date type variables according to the Jsonfromat format, and the browser get requests the node object to display the time normally.

    Add the annotation
    @DateTimeFormat (pattern= "Yyyy-mm-dd HH:mm:ss") to the definition of the object
    @JsonFormat (pattern= "Yyyy-mm-dd HH:mm:ss"). TimeZone = "Gmt+8")
    private Date crtdate;
    @DateTimeFormat (pattern= "Yyyy-mm-dd HH:mm:ss")
    @JsonFormat (pattern= "Yyyy-mm-dd HH:mm:ss", timezone = "gmt+8")
    private Date upddate;

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    SQL query Statement
     sql=string.format ("Select Id,uuid,upddate,crtdate from TRAN0401");
        try {
            Boolean result=st.execute (SQL);
            if (result)
            {
                rs=st.getresultset ();
                Jxnode node;
                while (Rs.next ())
                {                
                    node=new jxnode ();
                    String crtdate=rs.getstring ("crtdate"); Must be taken out as a string, or it will lose data
                    string upddate=rs.getstring ("Upddate");
                    Node.setcrtdate (Formatter.parse (crtdate));
                    Node.setupddate (Formatter.parse (upddate));
                }
            

SPRINGMVC returns JSON date format, @DatetimeFormat use note when using @responsebody

SPRINGMVC date format that returns JSON when using @responsebody

Prerequisite Knowledge: @ResponseBody The core class that returns the JSON string is Org.springframework.http.converter.json.MappingJacksonHttpMessageConverter, which uses the open source Third-party class library of Jackson. This is mainly the following two jar packages: Jackson-core-asl-1.6.4.jar;jackson-mapper-asl-1.6.4.jar.

Problem: Returns the date format of the JSON string when using @responsebody. The Date Type property returns a long timestamp by default, and how it can return a custom date format.

Solution: There are two ways to achieve this,

1, local modification (online more, but not recommended);

Inherit Jackson's abstract class: Jsonserializer<t>, and then add the annotation @jsonserialize on JavaBean's property getter ().

The code is as follows:

  Java code    import java.io.ioexception;   import java.text.simpledateformat;    import java.util.date;      import org.codehaus.jackson.jsongenerator;    import org.codehaus.jackson.jsonprocessingexception;   import  org.codehaus.jackson.map.jsonserializer;   import org.codehaus.jackson.map.serializerprovider;      /**   *  @description   Custom return json  date format processing   in the data grid  * @ author aokunsang   *  @date  2013-5-28   */   public class  customdateserializer extends jsonserializer<date> {            @Override        public void serialize (Date value,                 JsonGenerator  jsongenerator,                SerializerProvider  Provider)                throws  ioexception, jsonprocessingexception {            Simpledateformat sdf = new simpledateformat ("Yyyy-mm-dd hh:mm:ss");            jsongenerator.writestring (Sdf.format (value));        }  }  

How to use:

Java code