Actual Stickers:
Http://topic.csdn.net/u/20100720/10/c0b95705-308b-4ef4-b086-77b0c4c04522.html
Http://topic.csdn.net/u/20100802/14/8be14ec7-e560-4541-9d06-0a1a9bec17b7.html
-- Create a test environment
If object_id ('tb') is not null drop table TB
Go
Create Table TB
(
Id int identity,
Housename varchar (10 ),
Proid int,
ProCOUNT int
)
Go
Insert TB
Select 'a warehouse ', 1,100 union all
Select 'a warehouse ', 2, 50 Union all
Select 'B warehouse', 1, 60 Union all
Select 'B warehouse', 2, 70
-- Query
-- 1
If object_id ('f _ getproid ') is not null drop function f_getproid
Go
Create Function f_getproid (@ housename varchar (10 ))
Returns varchar (50)
As
Begin
Declare @ s varchar (50)
Select @ s = isnull (@ s + ',', '') + ltrim (proid) from TB where housename = @ housename
Return @ s
End
Go
If object_id ('f _ getprocount ') is not null drop function f_getprocount
Go
Create Function f_getprocount (@ housename varchar (10 ))
Returns varchar (50)
As
Begin
Declare @ s varchar (50)
Select @ s = isnull (@ s + ',', '') + ltrim (ProCOUNT) from TB where housename = @ housename
Return @ s
End
Go
Select housename, DBO. f_getproid (housename) proid, DBO. f_getprocount (housename) ProCOUNT from TB group by housename
Go
-- 2
Select housename,
Stuff (select ',' + ltrim (proid) from TB where housename = T. housename for XML Path (''), 1, 1,'') proid,
Stuff (select ',' + ltrim (ProCOUNT) from TB where housename = T. housename for XML Path (''), 1, 1,'') ProCOUNT
From TB t
Group by housename
-- Result
/*
(Four rows affected)
Housename proid ProCOUNT
-----------------------
Warehouse A, 50
Warehouse B, 70
(2 rows affected)
Housename proid ProCOUNT
-----------------------
Warehouse A, 50
Warehouse B, 70
(2 rows affected)
*/
/*
Title: Merge strings by a field (simple merge)
Author: AI xinjue Luo. Xin Hua)
Time:
Location: Shenzhen, Guangdong Province
Description: merges the following data into the value field by ID.
ID value
-----------
1 aa
1 bb
2 aaa
2 bbb
2 ccc
Expected results:
ID value
-----------------
1 aa, BB
2 AAA, BBB, CCC
That is: group by ID, sum of values (string addition)
*/
-- 1. SQL2000 can only be solved using custom functions
Create Table Tb (ID int, value varchar (10 ))
Insert into TB values (1, 'A ')
Insert into TB values (1, 'bb ')
Insert into TB values (2, 'aaa ')
Insert into TB values (2, 'bbb ')
Insert into TB values (2, 'ccc ')
Go
Create Function DBO. f_str (@ id int) returns varchar (100)
As
Begin
Declare @ STR varchar (1000)
Set @ STR =''
Select @ STR = @ STR + ',' + Cast (value as varchar) from TB where id = @ ID
Set @ STR = right (@ STR, Len (@ Str)-1)
Return @ Str
End
Go
-- Call a function
Select ID, value = DBO. f_str (ID) from TB group by ID
Drop function DBO. f_str
Drop table TB
-- 2. Methods in sql2005
Create Table Tb (ID int, value varchar (10 ))
Insert into TB values (1, 'A ')
Insert into TB values (1, 'bb ')
Insert into TB values (2, 'aaa ')
Insert into TB values (2, 'bbb ')
Insert into TB values (2, 'ccc ')
Go
Select ID, [value] = stuff (select ',' + [value] from TB t where id = Tb. ID for XML Path (''), 1, 1 ,'')
From TB
Group by ID
Drop table TB
-- 3. Use a cursor to merge data
Create Table Tb (ID int, value varchar (10 ))
Insert into TB values (1, 'A ')
Insert into TB values (1, 'bb ')
Insert into TB values (2, 'aaa ')
Insert into TB values (2, 'bbb ')
Insert into TB values (2, 'ccc ')
Go
Declare @ t table (ID int, value varchar (100) -- Define the result set table variable
-- Define and merge the cursor
Declare my_cursor cursor local
Select ID, value from TB
Declare @ id_old int, @ ID int, @ value varchar (10), @ s varchar (100)
Open my_cursor
Fetch my_cursor into @ ID, @ Value
Select @ id_old = @ ID, @ s =''
While @ fetch_status = 0
Begin
If @ ID = @ id_old
Select @ s = @ s + ',' + Cast (@ value as varchar)
Else
Begin
Insert @ T values (@ id_old, stuff (@ s, 1, 1 ,''))
Select @ s = ',' + Cast (@ value as varchar), @ id_old = @ ID
End
Fetch my_cursor into @ ID, @ Value
End
Insert @ T values (@ id_old, stuff (@ s, 1, 1 ,''))
Close my_cursor
Deallocate my_cursor
Select * From @ t
Drop table TB