String assignment to understand some of the differences between sizeof and strlen

#include <stdio.h>
#include <string.h> 
int main ()
{
 int a,i=0;
 char ch[10000];
 while (scanf ("%d", &a)!=eof&&a!=-1)
 {
  ch[i++]=a;
 }
 /*
  test Results The sizeof test is the total space   including the \ n
 strlen test is the length before the first hit
 */
  printf ("sizeof calculates the length:%d\n", sizeof (CH));
 printf ("strlen Calculated length:%d\n", strlen (CH));
 char th[]={"abc"};
 puts (TH);
 printf ("sizeof calculates the length:%d\n", sizeof (TH));
 printf ("strlen Calculated length:%d\n", strlen (TH));
// char sh[];
 char sh[]={' A ', ' B ', ' C ', ' \0  '};//char sh[]={' A ', ' B ', ' C '}; This is the wrong assignment so that the assignment does not follow the result of abcabc  printing   sizeof One less
// memset (sh,0,sizeof (SH));
 sh[0]= ' a ';
 puts (SH);
 printf ("sizeof calculates the length:%d\n", sizeof (SH));
 printf ("strlen Calculated length:%d\n", strlen (SH));
}//Test data
/*
1 0 2 0 1 0 0-1
Normally assumed to be  7
High precision operation when initialized is empty so add character 0 to calculate it's going to happen.
*/

String assignment method to understand some differences between sizeof and strlen