String truncation with Chinese characters appears half a "Chinese character" solution-C language source code

Chinese characters are encoded in double-byte, and for Chinese characters and single-byte characters, if the target intercept string contains only an odd number of single-byte characters, then the problem of half Chinese characters will appear. As shown below:

(1) No. 2nd South Guo Lu, Tianshui Qinzhou District (ICBC Qi Li dun sub-branches?) -- contains numeric characters, single byte .

(2) No. 3rd, building 20th, Jinfu Garden, Qilihe District City, Gold Harbour City?-- contains numeric characters, single-byte.

(3) Gansu Silver Xin Spring Catering Service Co., Ltd. (party committee---------- English format half brackets included.

　　The above is the result of capturing the first four bits of the string, where "? "For half a Chinese character coding display. To solve these problems, you can use the method of intercepting the last illegal character and replacing it with a valid character. The instance code is as follows:

#include <stdio.h>int Chkhalfchinese (char *buf,int len) {        int i = 0;    int cnt = 0;    int idx;    for (i=0;i<len;i++)     {           int value = buf[i]&0xff;        if (value>160)            {           cnt++;              idx=i;         }     }    if (cnt%2)     {        Buf[idx] = ';        return (1);     }    else        {        return (0)}      } int main (void) {  char str[44] = "Tianshui Qinzhou zone South Guo Lu 2 ah (ICBC Li Qi Dun sub-branches home";    if (Chkhalfchinese (str,40) ==1)  {    printf ("true\n");  }  else  {    printf ("false\n");  }  printf ("%s\n", &str);  return 0;}

　　

The program code is tested in the Linux environment and the results are as follows:

String truncation with Chinese characters appears half a "Chinese character" solution-C language source code