Swift "Ambiguous use of operator ' > '"

Http://stackoverflow.com/questions/25458548/swift-ambiguous-use-of-operator

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I have just downloaded xcode6-beta6. I am getting compiler Error "ambiguous use of operator ' > '" for following codes reversed = sorted(names, { s1, s2 in s1 > s2 } ) It is working before in Xcode6-beta5. The code is from Apple Swift documentationhttps://developer.apple.com/library/prerelease/ios/documentation/swift/ conceptual/swift_programming_language/closures.html#//apple_ref/doc/uid/tp40014097-ch11-xid_152 Any ideas? Swift Xcode6 ShareImprove this question Asked at 4:49Moin Uddin 1531

&nbs P;   what is  names   Defined as? –  mike s aug "at 4:51  &nbs P;   what type is  names ? I just tried it successfully in a playground with the following code:  let names = ["A", "B"]; let reversed = so rted (names, {s1, s2 in S1 > s2})  –  gary makin < Span class= "Relativetime-clean" title= "2014-08-23 05:20:12z" >aug "at 5:20   after seeing your comment I tested again and found the issue. Thanks. It ' s the issue with variable. In the swift document "reversed" is declared once and then used in everywhere and then this issue arises only for "implic It Returns from Single-expression Closures "and" shorthand Argument Names "cases. If you define new variable or constant then this error does not show Up. –  moin Uddin aug" at 14:13 I get the same error with var arrayToSort = ["a", "b"]; arrayToSort.sort{ $0 > $1 } . If I Change the operator to less than ( < ) the error disappears.–wottpal in 22:25 Add a Comment

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I had the same issue also with if ("aa" > "bb") { [...]} and Reversed = sorted (names, {$ > $}) Apparently XCode can ' t correctly infer the correct type "String" for the parameters, thus creating a ambiguity on the ope Rator. My solution have been to explicitly declare the type at least one of them which also makes the code more readable. Like in: if ( "AA" as String > "BB" { [...] } /span> Reversed = sorted (names, {$ as String > $ }) ShareImprove this answer Edited at 13:43 answered "at 13:27Michele Dall ' Agata 1331

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The This seems is a bug in the Foundation framework ' s bridging. It declares overrides of  ;  to handle comparing a  String  with an   nsstring   and  an  nsstring  and a  String , but those appear (in some cases) to conflict in matching. You can get around it (for some reason) by altering your syntax a little: reversed = (names, { S1, S2 in S1 > S2 } ShareImprove this answer answered Nov 4 ' at 15:34Nate Cook 26.6k2

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Swift "Ambiguous use of operator ' > '"