Taboo for The For loop

1. Error item

1 s=[11,22,33,44,55]2 for in range (Len (s)):  # will only happen once, Directly stored in memory, directly called.  3         print(i)        #  i=0                    i=1               i=2           i=34         del  s[i]       5         print(s)       #[ 22,33,44,55]    [22,44,55]      [22,44]     This time will be an error! 

2. The first method of solution

1s={"K1":"v1","K2":"v2","A3":"v3"}#This topic requires the deletion of the key value with K. 2s1={}#as excessive. 3  forIinchS:4     if "k"  not inchI#if there is no k in the key value:5S.setdefault (I,s[i])#Creates a new set of eligible key values into the S dictionary. At this point I is a variable, so you do not need to use quotation marks like new key-value pairs. 6S=s1#re-assigns the eligible key-value pairs to the original dictionary. This operation will completely overwrite the original dictionary without leaving any traces. 7 Print(s)

Taboo for The For loop