Test Question 1: Write a function and return the result of division of all elements in an array by the first element.

Test Question 1: Write a function and return the result of division of all elements in an array by the first element.

Many may think of the following:

Void divaarry (int * parray, int size)

{

For (INT I = size-1; I> = 0; I --)

{

Parray [I]/= parray [0];

}

}

Question 1: Can I write the loop right now?

Question 2: Check whether the divisor is zero

Obviously, question 1 is not acceptable. If you are writing:

For (INT I = 0; I <size; I ++)

{

Parray [I]/= parray [0];

}

In this way, when I = 0 is, the first element of the array is changed to 1, and the divisor will always be 1 instead of a number of the original array, which does not meet the requirements.

After modification:

Void divarray (int * parray, int size)

{

For (INT I = size-1; I> = 0; I --)

{

If (parray [0] = 0)

Cout <"error" <Endl;

Else

Parray [I]/= parray [0];

 

}

}

This can be found in writing, but there is a problem, when the size is large enough, the efficiency is wrong, because every time you have to judge whether the first element of the array is zero, this is a waste of time, you can place it outside the loop,

The result is compiled into the following code:

Void divarray (int * parray, int size)

{

If (parray [0] = 0) cout <"error" <Endl;

Else

For (INT I = size-1; I> = 0; I --)

{

Parray [I]/= parray [0];

}

}