The first process assessment--structural programming

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7-1 Hello world! (5 points)

The subject asks to write a program, output a short phrase "Hello world!".

Input format:

This topic is not entered.

Output format:

Output the phrase "Hello world!" in a row.

Program Design ideas: directly in the output code to fill in the content to be output.

Knowledge Points: System.out.println ("content to output");.

Operation Result:

7-2 for 1 to 100 and (10 points)

To write a program, calculate the expression 1 + 2 + 3 + ... + 100 value.

Input format:

No input in the subject.

Output format:

Output in the following format:

sum = 累加和

The design idea of the program : Use the FOR Loop statement with Sum=sum+i to complete the summation.

Knowledge Point:A For loop statement.

Operation Result:

7-3 sectional calculation of water consumption (15 points)

In order to encourage the residents to save water, the water company adopts a ladder-based pricing method, the residents should pay the charges.Y (yuan) and monthly water consumptionX (ton) Related: whenx no more than 15 tons, y =4x/3; over, y =2. 5x? 17. 5. Please write a program to achieve the calculation of water charges.

Input format:

The input gives a non-negative real number x in a row .

Output format:

The water charges that should be handed out on a line are accurate to 2 digits after the decimal point.

Input Sample 1:

12

Output Example 1:

16.00

Input Sample 2:

16

Output Example 2:

 22.50

The design idea of the program: use if () else if () statement to select two charge conditions, and then the number of the decimal point after the two digits of the precise output.

Knowledge Point:if SELECT statement; scanner input statement; printf controls output precision.

Operation Result:

7-4 printing 99 tables (20 points)

Below is a complete lower triangle 99 tables:

1*1=1   1*2=2   2*2=4   1*3=3   2*3=6   3*3=9   1*4=4   2*4=8   3*4=12  4*4=16  1*5=5   2*5=10  3*5=15  4*5=20  5*5=25  1*6=6   2*6=12  3*6=18  4*6=24  5*6=30  6*6=36  1*7=7   2*7=14  3*7=21  4*7=28  5*7=35  6*7=42  7*7=49  1*8=8   2*8=16  3*8=24  4*8=32  5*8=40  6*8=48  7*8=56  8*8=64  1*9=9   2*9=18  3*9=27  4*9=36  5*9=45  6*9=54  7*9=63  8*9=72  9*9=81  

The subject asks for any given positive integer N , the output from 1*1 N*N the partial table.

Input format:

The input gives a positive integer N (1≤ N ≤9) in a row.

Output format:

Output the lower triangular N*N table, where the right digit equals 4 digits, left-aligned.

Input Sample:

4

Sample output:

1*1=1   1*2=2   2*2=4   1*3=3   2*3=6   3*3=9   1*4=4   2*4=8   3*4=12  4*4=16  
程序的设计思路：利用for循环结构的嵌套来输出乘法表，并利用printf的左对齐来使结果对齐。
知识点：for循环结构的嵌套；printf可使输出左对齐。
运行结果：

Learning content	Number of lines of code	Blog words
Getting Started with Java	15
Input/Output data	49
Conditional branching statements	22
Looping statements	90
First-time Process assessment	44	488

The first process assessment--structured programming