The Python dictionary is sorted by value, with the list of dictionaries sorted by dictionary values

#-*-Encoding=utf-8-*-

Import operator

#按字典值排序 (the default is ascending)

x = {1:2, 3:4, 4:3, 2:1, 0:0}

sorted_x = sorted (X.iteritems (), Key=operator.itemgetter (1))

Print sorted_x

#[(0, 0), (2, 1), (1, 2), (4, 3), (3, 4)]

#如果要降序排序, you can specify Reverse=true

sorted_x = sorted (X.iteritems (), Key=operator.itemgetter (1), reverse=true)

Print sorted_x

#[(3, 4), (4, 3), (1, 2), (2, 1), (0, 0)]

#或者直接使用list的reverse方法将sorted_x顺序反转

#sorted_x. Reverse ()

#取代方法是, use lambda expressions

sorted_x = sorted (X.iteritems (), Key=lambda x:x[1])

Print sorted_x

#[(0, 0), (2, 1), (1, 2), (4, 3), (3, 4)]

sorted_x = sorted (X.iteritems (), Key=lambda x:x[1], reverse=true)

Print sorted_x

#[(3, 4), (4, 3), (1, 2), (2, 1), (0, 0)]

#包含字典dict的列表list的排序方法与dict的排序类似, as follows:

x = [{' Name ': ' Homer ', ' age ': ' the ', ' {' name ': ' Bart ', ' Age ': 10}]

sorted_x = sorted (x, Key=operator.itemgetter (' name '))

Print sorted_x

#[{' age ': Ten, ' name ': ' Bart '}, {' Age ':, ' name ': ' Homer '}]

sorted_x = sorted (x, Key=operator.itemgetter (' name '), reverse=true)

Print sorted_x

#[{' age ': "The ' name ': ' Homer '}, {' Age ': Ten, ' name ': ' Bart '}]

sorted_x = sorted (x, Key=lambda x:x[' name ')

Print sorted_x

#[{' age ': Ten, ' name ': ' Bart '}, {' Age ':, ' name ': ' Homer '}]

sorted_x = sorted (x, Key=lambda x:x[' name '], reverse=true)

Print sorted_x

#[{' age ': "The ' name ': ' Homer '}, {' Age ': Ten, ' name ': ' Bart '}]

The Python dictionary is sorted by value, with the list of dictionaries sorted by dictionary values