The input output by echo cannot call the onclick event.

The input output by echo cannot call the onclick event. & lt; SCRIPT & nbsp; language = JavaScript & nbsp; type = text/JavaScript & gt; function & nbsp; CheckAll (form) & nbsp; {for & nbsp; (var & nbsp; I = 0; input from I echo cannot be used to call the onclick event.

Function CheckAll (form ){
For (var I = 0; I Var e = form. elements [I];
If (e. name! = 'Chkall') e. checked = form. chkall. checked;
}
}

SCRIPT
Require_once 'sqlhelper. class. php ';
$ SqlHelper = new SqlHelper ();
$ SQL = "select * from user1 ";
$ Res = $ SqlHelper-> execute_dql ($ SQL );
$ Fields = mysql_num_fields ($ res );
$ Rows = mysql_num_rows ($ res );
Echo" ";
Echo" ";
For ($ I = 0; $ I <$ fields; $ I ++ ){
$ Fieldname = mysql_field_name ($ res, $ I );
Echo"$ Fieldname";
}
Echo"";
$ Num = 1;
While ($ row = mysql_fetch_row ($ res )){
Echo"";
Echo" ";
For ($ I = 0; $ I <$ fields; $ I ++ ){
Echo"$ Row [$ I]";
}
Echo"";
$ Num ++;
}
Echo"";
?>

Why does onclick = CheckAll (this. form) call js and share it with function? CheckAll (form )? {? (Var? I = 0;... 'data-pics = ''>
------ Solution --------------------
In addition, echo" "; Does not comply with php's conventions
------ Solution --------------------
This problem is most suitable for beginners to solve.

First, you need firefox and firebug plug-ins.

Then press F12 to enable this plug-in to refresh the page.

Then, if a JS error occurs in the "control" column, an error is reported, where is the problem?

If no error is reported, click this button and you will find the error.

For example, if I run your file and click that input



This form is undefined.

Moderator

If we don't have this capability, firebug will help us with special useful recommendations.