The longest common substring of an array with a suffix: poj 2774

Source: Internet
Author: User

Returns the length of the longest common substring of two strings using a suffix array.

For more information, see Luo Sui's paper.


[Cpp]
# Include <iostream>
# Include <cstdio>
# Include <cstring>
# Include <string>
# Include <algorithm>
# Include <cstdlib>
# Define maxn1000005
Using namespace std;
Int r [MAXN];
Int wa [MAXN], wb [MAXN], wv [MAXN], tmp [MAXN];
Int sa [MAXN]; // index range 1 ~ N value range 0 ~ N-1
Int cmp (int * r, int a, int B, int l)
{
Return r [a] = r [B] & r [a + l] = r [B + l];
}
Void da (int * r, int * sa, int n, int m)
{
Int I, j, p, * x = wa, * y = wb, * ws = tmp;
For (I = 0; I <m; I ++) ws [I] = 0;
For (I = 0; I <n; I ++) ws [x [I] = r [I] ++;
For (I = 1; I <m; I ++) ws [I] + = ws [I-1];
For (I = n-1; I> = 0; I --) sa [-- ws [x [I] = I;
For (j = 1, p = 1; p <n; j * = 2, m = p)
{
For (p = 0, I = n-j; I <n; I ++) y [p ++] = I;
For (I = 0; I <n; I ++)
If (sa [I]> = j) y [p ++] = sa [I]-j;
For (I = 0; I <n; I ++) wv [I] = x [y [I];
For (I = 0; I <m; I ++) ws [I] = 0;
For (I = 0; I <n; I ++) ws [wv [I] ++;
For (I = 1; I <m; I ++) ws [I] + = ws [I-1];
For (I = n-1; I> = 0; I --) sa [-- ws [wv [I] = y [I];
For (swap (x, y), p = 1, x [sa [0] = 0, I = 1; I <n; I ++)
X [sa [I] = cmp (y, sa [I-1], sa [I], j )? P-1: p ++;
}
}
Int rank [MAXN]; // index range 0 ~ N-1 value range 1 ~ N
Int height [MAXN]; // index from 1 (height [1] = 0)
Void calheight (int * r, int * sa, int n)
{
Int I, j, k = 0;
For (I = 1; I <= n; ++ I) rank [sa [I] = I;
For (I = 0; I <n; height [rank [I ++] = k)
For (k? K --: 0, j = sa [rank [I]-1]; r [I + k] = r [j + k]; ++ k );
Return;
}
Char s1 [MAXN], s2 [MAXN];
Int main ()
{
While (scanf ("% s", s1, s2 )! = EOF)
{
Int len = strlen (s1 );
Strcat (s1, "$ ");
Strcat (s1, s2 );
Int n = strlen (s1), m = 0;
For (int I = 0; I <n; I ++)
{
M = max (m, (int) s1 [I]);
R [I] = s1 [I];
}
R [n] = 0;
Da (r, sa, n + 1, m + 1); // note that n + 1 is the cause.
Calheight (r, sa, n );
Int res = 0;
For (int I = 1; I <n; I ++)
If (sa [I-1] <len & sa [I]> = len) | (sa [I-1]> = len & sa [I] <len) res = max (res, height [I]);
Printf ("% d \ n", res );
}
Return 0;
}

# Include <iostream>
# Include <cstdio>
# Include <cstring>
# Include <string>
# Include <algorithm>
# Include <cstdlib>
# Define maxn1000005
Using namespace std;
Int r [MAXN];
Int wa [MAXN], wb [MAXN], wv [MAXN], tmp [MAXN];
Int sa [MAXN]; // index range 1 ~ N value range 0 ~ N-1
Int cmp (int * r, int a, int B, int l)
{
Return r [a] = r [B] & r [a + l] = r [B + l];
}
Void da (int * r, int * sa, int n, int m)
{
Int I, j, p, * x = wa, * y = wb, * ws = tmp;
For (I = 0; I <m; I ++) ws [I] = 0;
For (I = 0; I <n; I ++) ws [x [I] = r [I] ++;
For (I = 1; I <m; I ++) ws [I] + = ws [I-1];
For (I = n-1; I> = 0; I --) sa [-- ws [x [I] = I;
For (j = 1, p = 1; p <n; j * = 2, m = p)
{
For (p = 0, I = n-j; I <n; I ++) y [p ++] = I;
For (I = 0; I <n; I ++)
If (sa [I]> = j) y [p ++] = sa [I]-j;
For (I = 0; I <n; I ++) wv [I] = x [y [I];
For (I = 0; I <m; I ++) ws [I] = 0;
For (I = 0; I <n; I ++) ws [wv [I] ++;
For (I = 1; I <m; I ++) ws [I] + = ws [I-1];
For (I = n-1; I> = 0; I --) sa [-- ws [wv [I] = y [I];
For (swap (x, y), p = 1, x [sa [0] = 0, I = 1; I <n; I ++)
X [sa [I] = cmp (y, sa [I-1], sa [I], j )? P-1: p ++;
}
}
Int rank [MAXN]; // index range 0 ~ N-1 value range 1 ~ N
Int height [MAXN]; // index from 1 (height [1] = 0)
Void calheight (int * r, int * sa, int n)
{
Int I, j, k = 0;
For (I = 1; I <= n; ++ I) rank [sa [I] = I;
For (I = 0; I <n; height [rank [I ++] = k)
For (k? K --: 0, j = sa [rank [I]-1]; r [I + k] = r [j + k]; ++ k );
Return;
}
Char s1 [MAXN], s2 [MAXN];
Int main ()
{
While (scanf ("% s", s1, s2 )! = EOF)
{
Int len = strlen (s1 );
Strcat (s1, "$ ");
Strcat (s1, s2 );
Int n = strlen (s1), m = 0;
For (int I = 0; I <n; I ++)
{
M = max (m, (int) s1 [I]);
R [I] = s1 [I];
}
R [n] = 0;
Da (r, sa, n + 1, m + 1); // note that n + 1 is the cause.
Calheight (r, sa, n );
Int res = 0;
For (int I = 1; I <n; I ++)
If (sa [I-1] <len & sa [I]> = len) | (sa [I-1]> = len & sa [I] <len) res = max (res, height [I]);
Printf ("% d \ n", res );
}
Return 0;
}

 

Contact Us

The content source of this page is from Internet, which doesn't represent Alibaba Cloud's opinion; products and services mentioned on that page don't have any relationship with Alibaba Cloud. If the content of the page makes you feel confusing, please write us an email, we will handle the problem within 5 days after receiving your email.

If you find any instances of plagiarism from the community, please send an email to: info-contact@alibabacloud.com and provide relevant evidence. A staff member will contact you within 5 working days.

A Free Trial That Lets You Build Big!

Start building with 50+ products and up to 12 months usage for Elastic Compute Service

  • Sales Support

    1 on 1 presale consultation

  • After-Sales Support

    24/7 Technical Support 6 Free Tickets per Quarter Faster Response

  • Alibaba Cloud offers highly flexible support services tailored to meet your exact needs.