The parameter problem of Python 3.x--function

Source: Internet
Author: User

-------------------parameter Type-----------------

1. Position parameters

def fun1 (x, y):
Print (x)
Print (y)
return 0

FUN1 (1,3)

2. Keyword parameters

def fun1 (x, y):
Print (x)
Print (y)
return 0

FUN1 (y=1,x=3)

3, the position parameter, the keyword parameter, the default parameter uses

def fun1 (x,y=6):
Print (x)
Print (y)
return 0

FUN1 (10)
FUN1 (10,7)
FUN1 (x=8)

4. Parameter group

*arge-------------------------

def fun1 (X,*args):
Print (x)
Print (args)
return 0

FUN1 (1,3,15,1,3,4)
Fun1 (1,* (3,15,1,3,4))

*kwarge-------------------------

def fun1 (X,**kwargs):
Print (x)
Print (Kwargs)
return 0

FUN1 (1,name = ' Harry ', age = 18)
FUN1 (1,**{name: ' Harry ', age:18})

Mixed use

def fun1 (X,y,age=17,*args,**kwargs):
Print (x)
Print (y)
Print (args)
Print (Kwargs)
return 0

FUN1 (1,3,15,1,3,4,name = ' Marry ', sex = ' M ')

The parameter problem of Python 3.x--function

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