The pointer must look!!! Detailed parsing of pointers

1. The difference between a pointer and a general variable
A variable is a data type used to store data, which is actually an address, and the data stored in the address is the value that the variable stores. You use scanf to assign values to a variable (such as a): scanf ("%d", &a); &a represents the address of variable a, which means entering a number and then putting the number in the address of a variable called a. Here's another way to assign a value to a. int *b = &a; scanf ("%d", b). Because the scanf parameter is ("A number", the address of the destination variable).

The pointer is a special variable, and it exists inside the stack, but the data it stores is the address of the other variable. Like what
int b = 1; int *a = &b; This means that a variable is defined and then its stored value is the address of variable B. So a = (address of b), *a = (the value (i.e. 1) of the address of B is stored). The pointer variable type int * float* double* char* depends on the data type of the normal variable it points to when you define the pointer variable.

2. Level Two Hands
int a = 1; int * b = &a; int **c = &b;
Here a pointer b is defined to store the address of a, and C is a level two pointer to store B's address. So C = (address of b), *c = (the value of the address stored by B, that is, B, that is, the address of a), **c = (the value of the address stored in B, that is, *b, that is, a stored value)

3. Replace array
int a[3] = {n/a};
int *b = A;
b = &a[0], *b = a[0], b+1 = a[1], * (b+1) = A[1], (b+2) = a[2],* (b+2) = a[2]

int A[3][3] = {{1,2,3},{4,5,6},{7,8,9}}
int *b[3];
int **c;
b = a ====> B = a[0], B = {)
b = A; B[1] = a[0][1];

c = A; c = {{1,2,3},{4,5,6},{7,8,9}} c[1] = a[1] = {4,5,6}
C[2][2] = a[2][2]

Hope can solve your doubts!!!

The pointer must look!!! Detailed parsing of pointers